Express the rate of this reaction in terms of the change in concentration of each of the reactants and products: $$ 2 \mathrm{~A}(g) \rightarrow \mathrm{B}(g)+\mathrm{C}(g) $$ When \([\mathrm{C}]\) is increasing at \(2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s},\) how fast is \([\mathrm{A}]\) decreasing?

Short Answer

Expert verified
The concentration of [A] is decreasing at 4 mol/L·s

Step by step solution

01

Identify the given information

The reaction is given by: \[2 \mathrm{~A}(g) \rightarrow \mathrm{B}(g) + \mathrm{C}(g) \] The rate of increase in concentration of \([\mathrm{C}]\) is given as \(2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\).
02

Write the rate expression for reactants and products

For the reaction \[2 \mathrm{~A}(g) \rightarrow \mathrm{B}(g) + \mathrm{C}(g)\], the rate of the reaction can be written in terms of the concentration changes of reactants and products. The rate \(r\) is: \[ -\frac{1}{2} \frac{d[A]}{dt} = \frac{d[B]}{dt} = \frac{d[C]}{dt} \]
03

Relate the given rate to the concentration change

Given that \( \frac{d[C]}{dt} = 2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \), use the rate expression to find the rate of change in concentration of \([ \mathrm{A} ]\). Substituting the given value: \[ \frac{d[C]}{dt} = 2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \] From the rate expression: \[ -\frac{1}{2} \frac{d[A]}{dt} = 2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \]
04

Solve for the rate of decrease in concentration of A

To find the value of \(\frac{d[A]}{dt}\), equate to the expression: Rearrange and solve for \(\frac{d[A]}{dt}\): \[ \frac{d[A]}{dt} = -2 \times 2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \] \[ \frac{d[A]}{dt} = -4 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

reaction rate
In chemistry, the reaction rate is a measure of how quickly a chemical reaction occurs. It is typically expressed as the change in concentration of a reactant or product per unit time. For example, in the reaction \[2 \mathrm{~A}(g) \rightarrow \mathrm{B}(g)+\mathrm{C}(g)\], the reaction rate can be observed by how fast the concentration of substances A, B, and C change over time.
The reaction rate is important because it helps us understand the speed at which reactions proceed, allowing for better control and optimization of chemical processes.
To express the rate of this reaction, we need to consider the decrease in concentration of reactant A and the increase in concentration of products B and C. These changes are linked together by the stoichiometry of the reaction, which tells us the proportions in which reactants and products participate in the reaction.
concentration change
Concentration change refers to the variation in the amount of reactants or products in a given volume over time. In our exercise, we are looking at the change in concentrations of A, B, and C.
For the reaction \[2 \mathrm{~A}(g) \rightarrow \mathrm{B}(g)+\mathrm{C}(g)\], the changes in concentration are related to one another. As the reaction proceeds:
  • The concentration of A decreases because A is being consumed.
  • The concentrations of B and C increase because they are being produced.
Given that the concentration of C is increasing at \(2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\), we use this information to find the concentration change of A. This direct relationship between the reactants and products allows us to calculate the rate at which the concentration of any participant in the reaction changes.
chemical kinetics
Chemical kinetics is the study of reaction rates and the factors that influence them. It involves understanding the steps through which reactants convert into products.
The rate at which a reaction occurs depends on various factors such as:
  • The concentration of reactants
  • The temperature of the system
  • The presence of a catalyst
  • The surface area of reactants
In our case, chemical kinetics helps us determine how the increase in concentration of product C affects the decrease in concentration of reactant A. This relationship is essential for predicting and controlling the behavior of chemical reactions in both laboratory and industrial settings.
rate expression
The rate expression is a mathematical way of linking the rate of a reaction to the concentration changes of its reactants and products.
For the reaction \[2 \mathrm{~A}(g) \rightarrow \mathrm{B}(g)+\mathrm{C}(g)\], the general rate expression can be written as:
\[ -\frac{1}{2} \frac{d[A]}{dt} = \frac{d[B]}{dt} = \frac{d[C]}{dt} \]
This expression shows the relationship between the rates of decrease of A and the rates of increase of B and C. The negative sign indicates that the concentration of A is decreasing, while the concentrations of B and C are increasing.
Given that \( \frac{d[C]}{dt} = 2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\), we can substitute this value into the rate expression to find the rate of decrease of A:
\[ -\frac{1}{2} \frac{d[A]}{dt} = 2 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \]
Solving for \( \frac{d[A]}{dt} \) gives us:
\[ \frac{d[A]}{dt} = -4 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \] This tells us that the concentration of A decreases at a rate of \(4 \mathrm{~mol} / \mathrm{L} \cdots\), consistent with the stoichiometry of the reaction.

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Most popular questions from this chapter

Experiment shows that the rate of formation of carbon tetrachloride from chloroform. \(\mathrm{CHCl}_{3}(g)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{CCl}_{4}(g)+\mathrm{HCl}(g)\) is first order in \(\mathrm{CHCl}_{3}, \frac{1}{2}\) order in \(\mathrm{Cl}_{2},\) and \(\frac{3}{2}\) order overall. Show that the following mechanism is consistent with the rate law: (1) \(\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{Cl}(g)\) [fast] (2) \(\mathrm{Cl}(g)+\mathrm{CHCl}_{3}(g) \longrightarrow \mathrm{HCl}(g)+\mathrm{CCl}_{3}(g)\) [slow] (3) \(\mathrm{CCl}_{3}(g)+\mathrm{Cl}(g) \longrightarrow \mathrm{CCl}_{4}(g) \quad[\) fast \(]\)

For the reaction \(4 \mathrm{~A}(g)+3 \mathrm{~B}(g) \longrightarrow 2 \mathrm{C}(g)\) the following data were obtained at constant temperature: $$ \begin{array}{cccc} \text { Experiment } & \begin{array}{c} \text { Initial Rate } \\ (\mathrm{mol} / \mathrm{L} \cdot \mathrm{min}) \end{array} & \begin{array}{c} \text { Initial [A] } \\ (\mathrm{mol} / \mathrm{L}) \end{array} & \begin{array}{c} \text { Initial [B] } \\ (\mathrm{mol} / \mathrm{L}) \end{array} \\ \hline 1 & 5.00 & 0.100 & 0.100 \\ 2 & 45.0 & 0.300 & 0.100 \\ 3 & 10.0 & 0.100 & 0.200 \\ 4 & 90.0 & 0.300 & 0.200 \end{array} $$ (a) What is the order with respect to each reactant? (b) Write the rate law. (c) Calculate \(k\) (using the data from Expt 1 ). (d) Using the value of \(k\) calculated in part (c), calculate the rate when \([\mathrm{A}]=\) \([\mathrm{B}]=0.400 \mathrm{~mol} / \mathrm{L}\).

Does a catalyst increase reaction rate by the same means as a rise in temperature does? Explain.

Carbon disulfide, a poisonous, flammable liquid, is an excellent solvent for phosphorus, sulfur, and some other nonmetals. A kinetic study of its gaseous decomposition gave these data: $$ \begin{array}{ccc} \text { Experiment } & \begin{array}{c} \text { Initial Rate } \\ (\mathrm{mol} / \mathrm{L} \cdot \mathrm{s}) \end{array} & \begin{array}{c} \text { Initial }\left[\mathrm{CS}_{2}\right] \\ (\mathrm{mol} / \mathrm{L}) \end{array} \\ \hline 1 & 2.7 \times 10^{-7} & 0.100 \\ 2 & 2.2 \times 10^{-7} & 0.080 \\ 3 & 1.5 \times 10^{-7} & 0.055 \\ 4 & 1.2 \times 10^{-7} & 0.044 \end{array} $$ (a) Write the rate law for the decomposition of \(\mathrm{CS}_{2}\). (b) Calculate the average value of the rate constant.

The proposed mechanism for a reaction is (1) \(\mathrm{A}(g)+\mathrm{B}(g) \rightleftharpoons \mathrm{X}(g) \quad\) [fast \(]\) (2) \(\mathrm{X}(g)+\mathrm{C}(g) \longrightarrow \mathrm{Y}(g) \quad\) [slow] (3) \(\mathrm{Y}(g) \longrightarrow \mathrm{D}(g) \quad\) [fast (a) What is the overall equation? (b) Identify the intermediate(s), if any. (c) What are the molecularity and the rate law for each step? (d) Is the mechanism consistent with the actual rate law: Rate \(=k[\mathrm{~A}][\mathrm{B}][\mathrm{C}] ?\) (e) Is the following one-step mechanism equally valid? \(\mathrm{A}(g)+\mathrm{B}(g)+\mathrm{C}(g) \longrightarrow \mathrm{D}(g) ?\)

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