Chapter 19: Problem 31
A buffer that contains \(1.05 M \mathrm{~B}\) and \(0.750 M \mathrm{BH}^{+}\) has a pH of \(9.50 .\) What is the \(\mathrm{pH}\) after \(0.0050 \mathrm{~mol}\) of \(\mathrm{HCl}\) is added to \(0.500 \mathrm{~L}\) of this solution?
Short Answer
Expert verified
The pH after the addition of HCl is approximately 9.49.
Step by step solution
01
Determine the amount of H+ ions added
Calculate the moles of HCl added. Since we are adding 0.0050 mol of HCl to the buffer, the number of moles of \(\text{H}^+\) ions added is 0.0050 mol, because HCl dissociates completely in water.
02
Calculate new concentrations after addition of HCl
The moles of \(\text{H}^+\) ions will react with an equivalent amount of base \(\text{B}\) in the buffer. The buffer reaction can be represented as: \[ \text{B} + \text{H}^+ \rightarrow \text{BH}^+ \] Therefore, the moles of \(\text{B}\) and \(\text{BH}^+\) change as follows: \(\text{new moles of } \text{B} = 1.05 \text{ M } \times 0.500 \text{ L} - 0.0050 \text{ mol} = 0.525 - 0.0050 = 0.520 \text{ mol}\) \(\text{new moles of } \text{BH}^+ = 0.750 \text{ M } \times 0.500 \text{ L} + 0.0050 \text{ mol} = 0.375 + 0.0050 = 0.380 \text{ mol}\)
03
Calculate new molar concentrations of buffer components
New concentrations are: \[ \text{new } [\text{B}] = \frac{0.520 \text{ mol}}{0.500 \text{ L}} = 1.04 \text{ M} \] \[ \text{new } [\text{BH}^+] = \frac{0.380 \text{ mol}}{0.500 \text{ L}} = 0.760 \text{ M} \]
04
Use the Henderson-Hasselbalch equation
The \(\text{pH}\) of a buffer solution is given by the Henderson-Hasselbalch equation: \[ \text{pH} = \text{p}K_a + \text{log} \frac{[\text{B}]}{[\text{BH}^+]} \] Given \(\text{pH} = 9.50\) initially, use this to find \(\text{p}K_a\). Rearrange the initial values to solve for \(\text{p}K_a \): \[ 9.50 = \text{p}K_a + \text{log} \frac{1.05}{0.750} \]
05
Solve for pK_a
Solving for \(\text{p}K_a\) gives: \[ \text{p}K_a = 9.50 - \text{log} \frac{1.05}{0.750} \] \[ \text{p}K_a = 9.50 - \text{log} \frac{1.05}{0.750} = 9.50 - 0.1448 = 9.3552 \]
06
Calculate the new pH
Now use the new concentrations to find the new \(\text{pH}\) after \(\text{HCl}\) is added: \[ \text{pH} = 9.3552 + \text{log} \frac{1.04}{0.760} = 9.3552 + \text{log} \frac{1.04}{0.760} = 9.3552 + 0.1367 = 9.4919 \] \(\text{pH} \approx 9.49\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Henderson-Hasselbalch equation
To calculate the pH of a buffer solution, we use an important tool known as the Henderson-Hasselbalch equation. This equation connects the pH of the solution with the concentrations of the acid and its conjugate base present in the solution. The Henderson-Hasselbalch equation is expressed as:\[ \text{pH} = \text{p}K_a + \text{log} \frac{[\text{B}]}{[\text{BH}^+]} \] Here, \(\text{p}K_a\) is the negative logarithm of the acid dissociation constant (\(K_a\)), which measures the strength of the acid.\( [\text{B}]\) represents the concentration of the base, and \([\text{BH}^+]\) represents the concentration of the conjugate acid.
This equation allows us to understand how the pH of a buffer solution changes when small amounts of acid or base are added. By maintaining specific molar concentrations of \( [\text{B}]\) and \([\text{BH}^+]\), we can keep the pH relatively stable.
This equation allows us to understand how the pH of a buffer solution changes when small amounts of acid or base are added. By maintaining specific molar concentrations of \( [\text{B}]\) and \([\text{BH}^+]\), we can keep the pH relatively stable.
acid-base reactions
An acid-base reaction involves the transfer of hydrogen ions (\(\text{H}^+\)) between the reactants. When a strong acid like hydrochloric acid (HCl) is added to a buffer solution, it dissociates completely to release \(\text{H}^+\) ions in the solution. These \(\text{H}^+\) ions will react with the base present in the buffer. In our example, the base is represented as \(\text{B}\). The reaction can be depicted as: \[ \text{B} + \text{H}^+ \rightarrow \text{BH}^+ \] This reaction illustrates how the base (\(\text{B}\)) neutralizes the added acid by converting into the conjugate acid (\(\text{BH}^+\)). Consequently, the concentrations of \(\text{B}\) and \(\text{BH}^+\) change, affecting the pH calculation. Understanding these reactions is crucial for grasping how buffer solutions work to resist drastic changes in pH when small amounts of acids or bases are introduced.
molar concentrations
Molar concentration, or molarity, is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution and is expressed in units of moles per liter (M). In the given exercise, we start with molar concentrations of \( 1.05 \text{ M} \) for \(\text{B}\) (the base) and \( 0.750 \text{ M} \) for \(\text{BH}^+\) (the conjugate acid).
Adding a known amount of hydrochloric acid (HCl) to a buffer system changes these concentrations. The calculation must account for the volume of the solution and the amount of acid added to find the new concentrations. After reacting with \(\text{B}\), the concentrations are recalculated using: \[ \text{new } [\text{B}] = \frac{\text{new moles of B}}{\text{volume of solution}} \] \[ \text{new } [\text{BH}^+] = \frac{\text{new moles of BH}^+}{\text{volume of solution}} \] Accurate concentration calculations are essential for correctly using the Henderson-Hasselbalch equation to determine the resulting pH of the buffer solution.
Adding a known amount of hydrochloric acid (HCl) to a buffer system changes these concentrations. The calculation must account for the volume of the solution and the amount of acid added to find the new concentrations. After reacting with \(\text{B}\), the concentrations are recalculated using: \[ \text{new } [\text{B}] = \frac{\text{new moles of B}}{\text{volume of solution}} \] \[ \text{new } [\text{BH}^+] = \frac{\text{new moles of BH}^+}{\text{volume of solution}} \] Accurate concentration calculations are essential for correctly using the Henderson-Hasselbalch equation to determine the resulting pH of the buffer solution.