What does a negative \(E_{\mathrm{cell}}^{\circ}\) indicate about a redox reaction? What does it indicate about the reverse reaction?

Short Answer

Expert verified
A negative \( E_{\mathrm{cell}}^{\circ} \) means the forward reaction is non-spontaneous, while the reverse reaction is spontaneous.

Step by step solution

01

Understanding Cell Potential

The cell potential, denoted as \( E_{\mathrm{cell}}^{\circ} \), indicates the ability of a redox reaction to proceed spontaneously. It is measured in volts (V).
02

Meaning of Negative Cell Potential

If \( E_{\mathrm{cell}}^{\circ} \) is negative, it means the reaction is non-spontaneous in the forward direction. This implies that the reaction requires an input of energy to occur.
03

Reverse Reaction Implication

For the reverse reaction, a negative \( E_{\mathrm{cell}}^{\circ} \) indicates that the reverse reaction would be spontaneous, as the sign of \( E_{\mathrm{cell}}^{\circ} \) would become positive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reaction
Redox reactions, short for reduction-oxidation reactions, are chemical processes in which electrons are transferred between substances. In these reactions, one substance loses electrons (oxidation), while another gains electrons (reduction). These reactions are fundamental in chemistry as they are involved in various biological processes and industrial applications.

Understanding redox reactions is crucial because:
  • They help explain how batteries generate electricity.
  • They are integral in processes like photosynthesis and cellular respiration.
  • They explain the corrosion and rusting of metals.
A key aspect of redox reactions is the cell potential, denoted as \(E_{\textrm{cell}}^{\textrm{circ}}\). It measures a reaction's ability to occur on its own. The sign of this potential tells us a lot about the reaction's spontaneity, which we'll explore further below.
Spontaneity
Spontaneity in chemistry refers to whether a reaction can proceed without any external energy input. When a reaction is spontaneous, it means it can occur by itself once it starts.

The cell potential, \(E_{\textrm{cell}}^{\textrm{circ}}\), helps us determine this. Here’s how:
  • If \(E_{\textrm{cell}}^{\textrm{circ}}\) is positive, the redox reaction is spontaneous. This means it releases energy as it proceeds.
  • If \(E_{\textrm{cell}}^{\textrm{circ}}\) is negative, the reaction is non-spontaneous and cannot proceed without adding energy.
When \(E_{\textrm{cell}}^{\textrm{circ}}\) is negative, it signals that energy needs to be put into the system for the reaction to go forward. Therefore, such reactions are not favorable under standard conditions. This ties directly into the notion of the reverse reaction, which we'll discuss next.
Reverse Reaction
When considering the reverse reaction, it's important to understand that the conditions of spontaneity change.

If a redox reaction has a negative \(E_{\textrm{cell}}^{\textrm{circ}}\), making it non-spontaneous in the forward direction, the reverse reaction becomes viable and spontaneous. This happens because the reverse reaction's cell potential would be the positive counterpart of the original negative value.

To illustrate:
  • For a reaction with \(E_{\textrm{cell}}^{\textrm{circ}} = -0.5 \) V, the reverse reaction will have \(E_{\textrm{cell}}^{\textrm{circ}} = +0.5 \) V.
It’s essential to consider both the forward and reverse reactions to fully understand a system's chemical behavior. This understanding ensures that energy requirements are met properly, and reactions are harnessed effectively in practical applications.

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Most popular questions from this chapter

Commercial electrolysis is performed on both molten \(\mathrm{NaCl}\) and aqueous \(\mathrm{NaCl}\) solutions. Identify the anode product, cathode product, species reduced, and species oxidized for the electrolysis of (a) molten \(\mathrm{NaCl}\) and (b) an aqueous solution of \(\mathrm{NaCl}\).

Why must an electrochemical process involve a redox reaction?

Commercial electrolytic cells for producing aluminum operate at \(5.0 \mathrm{~V}\) and \(100,000 \mathrm{~A}\). (a) How long does it take to produce exactly 1 metric ton ( \(1000 \mathrm{~kg}\) ) of aluminum? (b) How much electrical power (in kilowatt-hours, \(\mathrm{kW} \cdot \mathrm{h}\) ) is used \(\left(1 \mathrm{~W}=1 \mathrm{~J} / \mathrm{s} ; 1 \mathrm{~kW} \cdot \mathrm{h}=3.6 \times 10^{3} \mathrm{~kJ}\right) ?\) (c) If electricity costs \(\$ 0.123\) per \(\mathrm{kW} \cdot \mathrm{h}\) and cell efficiency is \(90 . \%\) what is the cost of electricity to produce exactly 1 lb of aluminum?

A voltaic cell has one half-cell with a Cu bar in a \(1.00 M\) \(\mathrm{Cu}^{2+}\) salt, and the other half-cell with a Cd bar in the same volume of a \(1.00 \mathrm{M} \mathrm{Cd}^{2+}\) salt. (a) Find \(E_{\mathrm{cell}}^{\circ}, \Delta G^{\circ},\) and \(K\) (b) As the cell operates, \(\left[\mathrm{Cd}^{2+}\right]\) increases; find \(E_{\text {cell }}\) and \(\Delta G\) when \(\left[\mathrm{Cd}^{2+}\right]\) is \(1.95 M\) (c) Find \(E_{\text {cell }}, \Delta G,\) and \(\left[\mathrm{Cu}^{2+}\right]\) at equilibrium.

Like any piece of apparatus, an electrolytic cell operates at less than \(100 \%\) efficiency. A cell depositing \(\mathrm{Cu}\) from a \(\mathrm{Cu}^{2+}\) bath operates for \(10 \mathrm{~h}\) with an average current of 5.8 A. If \(53.4 \mathrm{~g}\) of copper is deposited, at what efficiency is the cell operating?

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