Chapter 23: Problem 108
Draw a Lewis structure with lowest formal charges for \(\mathrm{MnO}_{4}^{-}\).
Short Answer
Expert verified
The Lewis structure for \text{MnO}_4^- has Mn in the center with four O atoms each connected by double bonds, maintaining overall -1 charge.
Step by step solution
01
- Determine the Total Number of Valence Electrons
To find the total number of valence electrons in \text{MnO}_4^- count the valence electrons from each atom. Manganese (Mn) has 7 valence electrons, and each oxygen (O) has 6 valence electrons. Also, consider the -1 charge by adding one more electron. Therefore, the total number of valence electrons is: \[7 (Mn) + 4 \times 6 (O) + 1 (charge) = 32 \text{ electrons} \].
02
- Draw the Skeletal Structure
Place the manganese atom (Mn) in the center and surround it with four oxygen (O) atoms, forming a basic skeletal structure like this: Mn-O-O-O-O.
03
- Distribute Electrons to Form Bonds
Connect Mn to each O with a single bond first, which uses 8 electrons (2 electrons per bond): \[ 32 - 8 = 24 \text{ electrons remaining} \].
04
- Complete the Octet for Oxygen Atoms
Distribute the remaining 24 electrons to the oxygen atoms to complete their octets. Each oxygen needs 6 more electrons (3 lone pairs): \[6 \times 4 = 24 \text{ electrons} \]. This uses up all of the remaining 24 electrons.
05
- Check Formal Charges
Calculate the formal charge for each atom. For oxygen atoms each with 6 lone pair electrons and 1 single bond: \[FC_{O} = 6 - (6 + 1) = -1 \]. For manganese: assume double bonds to make formal charges lower.
06
- Adjust for Lowest Formal Charges
Replace each single bond between Mn and O with double bonds until the formal charges are minimized. Properly adjusted structure is: One Mn with 4 double-bonded O atoms and overall -1 charge.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
valence electrons
Understanding valence electrons is crucial for drawing the Lewis structure of \(\text{MnO}_4^-\). Valence electrons are the outermost electrons of an atom and participate in chemical bonding. Manganese (Mn) has 7 valence electrons, each oxygen (O) has 6, and since \(\text{MnO}_4^-\) carries a -1 charge, we add one more electron. This totals:
\(\text{7 (from Mn) + 4 \times 6 (from 4 oxygen atoms) + 1 (additional electron from the charge) = 32 electrons}\).
These valence electrons are distributed to form bonds and lone pairs around the atoms to satisfy their valence requirements.
Let's make sure we count and distribute them accurately to reflect the real molecular structure.
\(\text{7 (from Mn) + 4 \times 6 (from 4 oxygen atoms) + 1 (additional electron from the charge) = 32 electrons}\).
These valence electrons are distributed to form bonds and lone pairs around the atoms to satisfy their valence requirements.
Let's make sure we count and distribute them accurately to reflect the real molecular structure.
formal charges
Formal charge calculations help us find the most stable Lewis structure by showing how the electron count differs from what's standard for each atom. The formula for formal charge is:
\(\text{FC} = \text{V} - (\text{N}_{\text{L.P.}} + \text{N}_{\text{B.P.}}/2)\)
where \(\text{V}\) is the number of valence electrons, \(\text{N}_{\text{L.P.}}\) is the number of lone pair electrons, and \(\text{N}_{\text{B.P.}}\) is the number of bonding electrons.
For oxygen in the original setup with 6 lone pairs and one single bond:
\(\text{FC} = 6 - (6+1) = -1\).
For manganese, changing single bonds to double bonds lowers formal charges, ideally, manganese should have formal charge close to zero, helping us spot the most stable structure.
\(\text{FC} = \text{V} - (\text{N}_{\text{L.P.}} + \text{N}_{\text{B.P.}}/2)\)
where \(\text{V}\) is the number of valence electrons, \(\text{N}_{\text{L.P.}}\) is the number of lone pair electrons, and \(\text{N}_{\text{B.P.}}\) is the number of bonding electrons.
For oxygen in the original setup with 6 lone pairs and one single bond:
\(\text{FC} = 6 - (6+1) = -1\).
For manganese, changing single bonds to double bonds lowers formal charges, ideally, manganese should have formal charge close to zero, helping us spot the most stable structure.
octet rule
The octet rule states that atoms tend to form bonds until they have 8 electrons in their valence shell, mimicking the electron configuration of noble gases. Each oxygen atom in \(\text{MnO}_4^-\) should follow this:
Connect Mn to each O with single bonds first, using up 8 electrons (2 per bond).
Then, complete each O's octet with 6 more electrons (3 lone pairs).
After distributing 24 more electrons among O atoms, check if each atom satisfies the octet rule. Manganese might exceed 8 electrons because it is in period 3, having access to 3d orbitals, allowing expanded octets necessary for correct formal charges.
Connect Mn to each O with single bonds first, using up 8 electrons (2 per bond).
Then, complete each O's octet with 6 more electrons (3 lone pairs).
After distributing 24 more electrons among O atoms, check if each atom satisfies the octet rule. Manganese might exceed 8 electrons because it is in period 3, having access to 3d orbitals, allowing expanded octets necessary for correct formal charges.
molecular structure
Drawing the correct molecular structure requires balancing all these principles. The process is:
- Place Mn centrally and connect 4 Os around it.
- Use single bonds (8 electrons), then distribute remaining electrons to satisfy Os' octets (24 electrons).
- Check, correct formal charges by replacing single bonds with double bonds until charges are minimized (3 double bonds and 1 single ensures each atom follows the rules).
- This forms a valid Lewis structure: central Mn with double bonds to each O, maintaining overall –1 charge.