Chapter 23: Problem 111
In \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3},\) the \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) ion absorbs visible light in the blue-violet range, and the compound is yellow- orange. In \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Br}_{3}\), the \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) ion absorbs visible light in the red range, and the compound is blue-gray. Explain these differences in light absorbed and compound color.
Short Answer
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