Write the general electron configuration of a transition element (a) in Period \(5 ;\) (b) in Period 6 .

Short Answer

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(a) [Kr] 4d^{1-10} 5s^{0-2}; (b) [Xe] 4f^{0-14} 5d^{1-10} 6s^{0-2}

Step by step solution

01

Identify the Position in the Periodic Table

Transition elements are found in groups 3-12 of the periodic table. For (a) Period 5 and (b) Period 6, identify the respective blocks.
02

Determine the General Electron Configuration Pattern

For transition elements, the general electron configuration follows the pattern \[ \text{[Noble gas]} (n-1)d^{1-10} ns^{0-2} \] where n is the period number.
03

Apply the Pattern to Period 5 Transition Elements

For Period 5, n = 5. The general electron configuration for these transition elements is \[ \text{[Kr]} 4d^{1-10} 5s^{0-2} \]
04

Apply the Pattern to Period 6 Transition Elements

For Period 6, n = 6. The general electron configuration for these transition elements is \[ \text{[Xe]} 4f^{0-14} 5d^{1-10} 6s^{0-2} \]. Note that Period 6 includes the lanthanides.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table
The Periodic Table is a valuable tool that arranges all known elements in a systematic way based on their atomic number, electron configurations, and recurring chemical properties. Each row in the Periodic Table is called a 'period,' while each column is referred to as a 'group.' Elements are broadly classified into metals, nonmetals, and metalloids.

Transition metals are located in groups 3-12 and periods 4-7. These elements play a significant role in various chemical reactions due to their ability to form multiple oxidation states and complex ions. Understanding the layout of the Periodic Table is crucial for identifying element properties and predicting behaviors in reactions.
Electron Configuration
Electron configuration describes the distribution of electrons in an atom's orbitals. It's essential to understand this concept to predict an element's chemical properties and how it will interact with other elements. The general format for electron configuration is writing out the electrons in their respective energy levels and sublevels (s, p, d, f).

For example, the electron configuration for Carbon (atomic number 6) is 1s² 2s² 2p². Orbital filling follows specific rules, such as the Aufbau principle (electrons occupy the lowest energy orbitals first), Hund's Rule (every orbital in a subshell is singly occupied before any orbital is doubly occupied), and the Pauli Exclusion Principle (no two electrons can have the same set of quantum numbers). Understanding these rules is fundamental for grasping more complex configurations, especially for transition metals.
Transition Metals
Transition metals are a unique group of elements found in the d-block of the Periodic Table, specifically in groups 3-12. They are characterized by partially filled d-orbitals, which allow for complex electron configurations and a variety of oxidation states. This flexibility is why transition metals are often used as catalysts and in alloy formation.

In Period 5 (n=5), the general electron configuration for transition elements is \[ \text{[Kr]} 4d^{1-10} 5s^{0-2} \]. For Period 6 (n=6), including the lanthanides, the configuration extends to \[ \text{[Xe]} 4f^{0-14} 5d^{1-10} 6s^{0-2} \]. The presence of empty or partially filled d-orbitals allows transition metals to form colored compounds, exhibit magnetic properties, and engage in unique bonding scenarios essential for industrial applications.
Lanthanides
The Lanthanides, often referred to as rare earth elements, are a group of 15 metallic elements from lanthanum (La) to lutetium (Lu) in the Periodic Table. They are found in Period 6 and follow the f-block, characterized by filling the 4f orbitals. Lanthanides usually have similar chemical properties due to their similar electron configurations.

The general electron configuration for lanthanides is \[ \text{[Xe]} 4f^{0-14} 5d^{0-1} 6s^{2} \]. These elements are known for their magnetic and phosphorescent properties, making them essential in various high-tech applications, such as permanent magnets, phosphors in display screens, and catalysts. Understanding the properties and configurations of lanthanides is crucial for advancements in technology and materials science.

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Most popular questions from this chapter

Two bidentate ligands used extensively in analytical chemistry are bipyridyl (bipy) and ortho-phenanthroline \((o\) -phen \():\) Draw structures and discuss the possibility of isomers for (a) [Pt(bipy) \(\mathrm{Cl}_{2}\) ] (b) \(\left[\mathrm{Fe}(o-\mathrm{phen})_{3}\right]^{3+}\) (c) [Co(bipy) \(\left._{2} \mathrm{~F}_{2}\right]^{+}\) (d) \(\left[\mathrm{Co}(o-\mathrm{phen})\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}\right]^{2+}\)

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In many species, a transition metal has an unusually high or low oxidation state. Write balanced equations for the following and find the oxidation state of the transition metal in the product: (a) Iron(III) ion reacts with hypochlorite ion in basic solution to form ferrate ion \(\left(\mathrm{FeO}_{4}^{2-}\right), \mathrm{Cl}^{-},\) and water. (b) Potassium hexacyanomanganate(II) reacts with \(\mathrm{K}\) metal to form \(\mathrm{K}_{6}\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]\) (c) Heating sodium superoxide \(\left(\mathrm{NaO}_{2}\right)\) with \(\mathrm{Co}_{3} \mathrm{O}_{4}\) produces \(\mathrm{Na}_{4} \mathrm{CoO}_{4}\) and \(\mathrm{O}_{2}\) gas. (d) Vanadium(III) chloride reacts with Na metal under a CO atmosphere to produce \(\mathrm{Na}\left[\mathrm{V}(\mathrm{CO})_{6}\right]\) and \(\mathrm{NaCl} .\) (e) Barium peroxide reacts with nickel(II) ions in basic solution to produce \(\mathrm{BaNiO}_{3}\) (f) Bubbling CO through a basic solution of cobalt(II) ion produces \(\left[\mathrm{Co}(\mathrm{CO})_{4}\right]^{-}, \mathrm{CO}_{3}^{2-},\) and water. (g) Heating cesium tetrafluorocuprate(II) with \(\mathrm{F}_{2}\) gas under pressure gives \(\mathrm{Cs}_{2} \mathrm{CuF}_{6}\) (h) Heating tantalum(V) chloride with Na metal produces \(\mathrm{NaCl}\) and \(\mathrm{Ta}_{6} \mathrm{Cl}_{15},\) in which half of the \(\mathrm{Ta}\) is in the +2 state. (i) Potassium tetracyanonickelate(II) reacts with hydrazine \(\left(\mathrm{N}_{2} \mathrm{H}_{4}\right)\) in basic solution to form \(\mathrm{K}_{4}\left[\mathrm{Ni}_{2}(\mathrm{CN})_{6}\right]\) and \(\mathrm{N}_{2}\) gas.

What electronic feature must a donor atom of a ligand have?

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