In which compound does Cr exhibit greater metallic behavior, \(\mathrm{CrF}_{2}\) or \(\mathrm{CrF}_{6} ?\) Explain.

Short Answer

Expert verified
Cr in \(\text{CrF}_2\) exhibits greater metallic behavior.

Step by step solution

01

Determine the Oxidation States

Identify the oxidation state of Chromium (Cr) in both compounds. In \(\text{CrF}_2\), Cr is in the +2 oxidation state. In \(\text{CrF}_6\), Cr is in the +6 oxidation state.
02

Understand Oxidation State Impact

Remember that higher oxidation states generally mean less metallic character because the element has a higher tendency to accept electrons (acting more like a non-metal).
03

Compare the Two Compounds

Given that \(\text{CrF}_2\)'s Cr is in the +2 oxidation state and \(\text{CrF}_6\)'s Cr is in the +6 oxidation state, the Cr in \(\text{CrF}_2\) has greater metallic behavior as it is in a lower oxidation state.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

metallic behavior
Metallic behavior refers to how an element exhibits properties such as luster, electrical conductivity, and the ability to lose electrons to form positive ions. When we talk about elements like Chromium (Cr), their metallic behavior can change dramatically based on their oxidation state. In general, lower oxidation states often show more metallic character because the element is more likely to lose electrons rather than gain them.
When Chromium is in a lower oxidation state, like +2 in \(\text{CrF}_2\), it has more metallic behavior. This is because it's more willing to give up its electrons, behaving more like a typical metal. Conversely, when Chromium is in a higher oxidation state, like +6 in \(\text{CrF}_6\), it tends to behave less like a metal and more like a non-metal. This higher oxidation state indicates that Chromium is more likely to accept electrons, reducing its metallic character.
Chromium compounds
Chromium can form a variety of compounds, each with different properties depending on its oxidation state. Chromium fluoride compounds like \(\text{CrF}_2\) and \(\text{CrF}_6\) are good examples to consider.
In \(\text{CrF}_2\), Chromium is in the +2 oxidation state. This compound exhibits more metallic properties. Examples include being a better conductor of electricity and having a shinier appearance.
In \(\text{CrF}_6\), Chromium is in the +6 oxidation state. This state is less metallic. Chromium in this compound has a strong tendency to accept electrons, making it more non-metal like.
So by comparing \(\text{CrF}_2\) and \(\text{CrF}_6\), you can see that the properties of Chromium change significantly with its oxidation states, influencing its behavior in reactions and its physical and chemical characteristics.
electron acceptance
Understanding electron acceptance is crucial in chemistry, especially when evaluating an element's metallic or non-metallic behavior. Electron acceptance refers to the ability of an atom or ion to accept additional electrons. This characteristic is more pronounced in higher oxidation states.
In the case of Chromium, when it is in the +6 oxidation state as in \(\text{CrF}_6\), it has a high electron acceptance tendency. This makes it behave more like a non-metal. It readily gains electrons, making it a strong oxidizing agent.
In contrast, when Chromium is in the +2 oxidation state as in \(\text{CrF}_2\), it is less inclined to accept electrons. Instead, it tends to lose electrons, exhibiting more metallic properties. This decreased electron acceptance is why \(\text{CrF}_2\) shows greater metallic behavior compared to \(\text{CrF}_6\).

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Most popular questions from this chapter

In \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3},\) the \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) ion absorbs visible light in the blue-violet range, and the compound is yellow- orange. In \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Br}_{3}\), the \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) ion absorbs visible light in the red range, and the compound is blue-gray. Explain these differences in light absorbed and compound color.

When \(\mathrm{MCl}_{4}\left(\mathrm{NH}_{3}\right)_{2}\) is dissolved in water and treated with AgNO \(_{3}, 2\) mol of \(\mathrm{AgCl}\) precipitates immediately for each mole of \(\mathrm{MCl}_{4}\left(\mathrm{NH}_{3}\right)_{2} .\) Give the coordination number of \(\mathrm{M}\) in the complex.

Give systematic names for the following formulas: (a) \(\mathrm{K}\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]\) (b) \(\mathrm{Na}_{2}\left[\mathrm{CdCl}_{4}\right]\) (c) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Br}\right] \mathrm{Br}_{2}\)

Give systematic names for the following formulas: (a) \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{2}\) (b) \(\left[\mathrm{Cr}(\mathrm{en})_{3}\right]\left(\mathrm{ClO}_{4}\right)_{3}\) (c) \(\mathrm{K}_{4}\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]\)

Octahedral [Ni(NH \(_{3}\) ) \(\left._{6}\right]^{2+}\) is paramagnetic, whereas planar \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) is diamagnetic, even though both metal ions are \(d^{8}\) species. Explain.

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