Chapter 23: Problem 25
Which oxide, \(\mathrm{Mn}_{2} \mathrm{O}_{3}\) or \(\mathrm{Mn}_{2} \mathrm{O}_{7}\), is more basic in water? Why?
Short Answer
Expert verified
Mn2O3 is more basic than Mn2O7 because it has manganese in a lower oxidation state (+3).
Step by step solution
01
- Understand the Oxides
Recognize the chemical formulas for the manganese oxides given: ame{Mn}_2O_3 and ame{Mn}_2O_7. These are manganese(III) oxide and manganese(VII) oxide respectively.
02
- Determine Oxidation States
Calculate the oxidation states for manganese in each oxide. For ame{Mn}_2O_3: Each oxygen has an oxidation state of -2. Therefore, the manganese oxidation state in ame{Mn}_2O_3 is +3. For ame{Mn}_2O_7: Each oxygen has an oxidation state of -2. Therefore, the manganese oxidation state in ame{Mn}_2O_7 is +7.
03
- Review Basicity Concept
Recall that basicity of oxides in water is generally determined by the oxidation state of the metal. Oxides of metals in lower oxidation states tend to be more basic, while oxides in higher oxidation states tend to be more acidic.
04
- Compare Basicity Based on Oxidation State
Since ame{Mn} in ame{Mn}_2O_3 has a +3 oxidation state and in ame{Mn}_2O_7 has a +7 oxidation state, ame{Mn}_2O_3 is more basic than ame{Mn}_2O_7 because +3 is a lower oxidation state compared to +7.
05
- Conclude Basicity
Based on the oxidation states and basicity concept, ame{Mn}_2O_3 (manganese(III) oxide) is more basic than ame{Mn}_2O_7 (manganese(VII) oxide).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation State
Understanding oxidation states is crucial when discussing manganese oxides. The oxidation state indicates the degree of oxidation of an atom in a compound. It's represented by integers, which can be positive, negative, or zero. For instance, in \(\text{Mn}_2O_3\), each oxygen has an oxidation state of -2. Since the total charge must equal zero, we can calculate the oxidation state of Mn as follows: \[2 \times x + 3 \times (-2) = 0\] Solving for x, we get: \[2x - 6 = 0 \implies x = +3\] Similarly, in \(\text{Mn}_2O_7\), since there are 7 oxygens: \[2 \times x + 7 \times (-2) = 0\] Solving for x: \[2x - 14 = 0 \implies x = +7\] Thus, the oxidation states of Mn are +3 in \(\text{Mn}_2O_3\) and +7 in \(\text{Mn}_2O_7\).
Metal Oxides
Metal oxides are compounds formed by metals combined with oxygen. They can exist in various oxidation states, influencing their physical and chemical properties. Manganese oxides demonstrate this, with \(\text{Mn}_2O_3\) being manganese(III) oxide and \(\text{Mn}_2O_7\) being manganese(VII) oxide. The properties of these oxides, such as basicity and acidity, are closely tied to the oxidation state of the metal. Higher oxidation states generally result in more acidic oxides, whereas lower oxidation states often produce more basic oxides.
Basicity and Acidity of Oxides
The basicity and acidity of metal oxides depend on the oxidation state of the metal. Oxides with metals in lower oxidation states are more basic. Conversely, oxides with metals in higher oxidation states are more acidic. In an aqueous solution:
- Manganese(III) oxide (\(\text{Mn}_2O_3\)) with Mn in a +3 oxidation state tends to be basic.
- Manganese(VII) oxide (\(\text{Mn}_2O_7\)) with Mn in a +7 oxidation state tends to be acidic.
Chemical Formulas
Chemical formulas represent the composition of molecules using symbols for each element and numbers indicating their ratios. For example:
- \(\text{Mn}_2O_3\) means there are 2 manganese atoms and 3 oxygen atoms.
- \(\text{Mn}_2O_7\) indicates 2 manganese atoms and 7 oxygen atoms.