How many moles of \(\mathrm{H}^{+}\) ions are present in each of the following aqueous solutions? (a) \(1.4 \mathrm{~mL}\) of \(0.75 \mathrm{M}\) hydrobromic acid (b) \(2.47 \mathrm{~mL}\) of \(1.98 \mathrm{M}\) hydriodic acid (c) \(395 \mathrm{~mL}\) of \(0.270 \mathrm{M}\) nitric acid

Short Answer

Expert verified
0.00105 moles, 0.0048906 moles, 0.10665 moles

Step by step solution

01

- Understand the relationship between molarity, volume, and moles

Molarity (M) is defined as moles of solute per liter of solution. To find the number of moles, use the formula: \[ \text{Moles} = \text{Molarity} \times \text{Volume (in liters)} \]
02

- Convert the given volume to liters

Volumes are given in milliliters (mL), and we need to convert them to liters (L) since molarity is in moles per liter. Use the conversion: \[ 1 \text{ mL} = 0.001 \text{ L} \]
03

- Calculate moles for each solution

(a) Hydrobromic acid: Volume = 1.4 mL = 0.0014 L, Molarity = 0.75 M\[ \text{Moles} = 0.75 \text{ M} \times 0.0014 \text{ L} = 0.00105 \text{ moles} \] (b) Hydriodic acid: Volume = 2.47 mL = 0.00247 L, Molarity = 1.98 M\[ \text{Moles} = 1.98 \text{ M} \times 0.00247 \text{ L} = 0.0048906 \text{ moles} \] (c) Nitric acid: Volume = 395 mL = 0.395 L, Molarity = 0.270 M\[ \text{Moles} = 0.270 \text{ M} \times 0.395 \text{ L} = 0.10665 \text{ moles} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

molarity
Molarity is a fundamental concept in chemistry, especially when dealing with solutions. It measures the concentration of a solute in a given volume of solution, using the formula: \(M = \frac{\text{Moles of solute}}{\text{Volume of solution in liters}} \). This means that molarity (M) tells you how many moles of a substance are present in one liter of a solution. For example, a solution with 1 mole of table salt in 1 liter of water has a molarity of 1 M (1 mol/L). Molarity is essential in stoichiometry calculations and helps in predicting how different solutions will react with each other. Knowing the molarity of a solution allows you to determine the amount of solute present, which is the key to solving many chemistry problems.
volume conversion
Volume conversion is critical when working with solutions, especially because molarity is based on liters. Given volumes often come in milliliters (mL), which must be converted to liters (L). Take note that 1 liter is equivalent to 1,000 milliliters. Therefore, to convert milliliters to liters, you simply multiply the number of milliliters by 0.001. For example:
  • 1 mL = 0.001 L
  • 50 mL = 50 × 0.001 = 0.05 L
By ensuring the volume is in liters, you can correctly use the molarity formula: \(\text{Moles} = \text{Molarity} \times \text{Volume in liters} \). Let's use the example from the exercise:
  • 1.4 mL = 1.4 × 0.001 = 0.0014 L
  • 2.47 mL = 2.47 × 0.001 = 0.00247 L
  • 395 mL = 395 × 0.001 = 0.395 L
Once the conversion is complete, you can easily calculate the number of moles using the molarity formula.
aqueous solutions
An aqueous solution is simply a solution where water is the solvent. In other words, substances are dissolved in water to form these solutions. Water is a universal solvent, which means it can dissolve many compounds and is commonly used in chemistry. Aqueous solutions are particularly important in understanding how different substances react in water. Many reactions, such as acid-base reactions or ionic dissociations, happen in aqueous solutions. For example, acids like hydrobromic acid (HBr), hydriodic acid (HI), and nitric acid (HNO3) dissolve in water to release \(\mathrm{H}^{+}\) ions, contributing to the characteristics of stomach acid. To summarize, when dealing with problems involving aqueous solutions:
  • Determine the substance's molarity.
  • Convert the given volume to liters.
  • Use the molarity formula to find the number of moles desired.
Follow these steps, and you'll be able to navigate calculations involving aqueous solutions effectively.

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Most popular questions from this chapter

What occurs on the molecular level when an ionic compound dissolves in water?

In a titration of \(\mathrm{HNO}_{3}\), you add a few drops of phenolphthalein indicator to \(50.00 \mathrm{~mL}\) of acid in a flask. You quickly add \(20.00 \mathrm{~mL}\) of \(0.0502 \mathrm{M} \mathrm{NaOH}\) but overshoot the end point, and the solution turns deep pink. Instead of starting over, you add \(30.00 \mathrm{~mL}\) of the acid, and the solution turns colorless. Then, it takes \(3.22 \mathrm{~mL}\) of the \(\mathrm{NaOH}\) to reach the end point. (a) What is the concentration of the \(\mathrm{HNO}_{3}\) solution? (b) How many moles of \(\mathrm{NaOH}\) were in excess after the first addition?

Sodium peroxide \(\left(\mathrm{Na}_{2} \mathrm{O}_{2}\right)\) is often used in self-contained breathing devices, such as those used in fire emergencies, because it reacts with exhaled \(\mathrm{CO}_{2}\) to form \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) and \(\mathrm{O}_{2}\). How many liters of respired air can react with \(80.0 \mathrm{~g}\) of \(\mathrm{Na}_{2} \mathrm{O}_{2}\) if each liter of respired air contains \(0.0720 \mathrm{~g}\) of \(\mathrm{CO}_{2} ?\)

Are the following instructions for diluting a \(10.0 M\) solution to a \(1.00 \mathrm{M}\) solution correct: "Take \(100.0 \mathrm{~mL}\) of the \(10.0 \mathrm{M}\) solution and add \(900.0 \mathrm{~mL}\) water"? Explain.

Does an aqueous solution of each of the following conduct an electric current? Explain. (a) Cesium bromide (b) Hydrogen iodide

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