What is the mass of oxygen in 148 grams of calcium hydroxide \(\left(\mathrm{Ca}(\mathrm{OH})_{2}\right)\) ? (A) 24 grams (B) 32 grams (C) 48 grams (D) 64 grams

Short Answer

Expert verified
The mass of oxygen in 148 grams of calcium hydroxide is approximately 64 grams (option D).

Step by step solution

01

Calculate the Molar Mass of Calcium Hydroxide

First, calculate the molar mass of calcium hydroxide. The molecular formula for calcium hydroxide is \(Ca(OH)_{2}\). The molar mass is calculated as follows: \(M_{Ca(OH)_{2}} = M_{Ca} + 2(M_{O} + M_{H}) = 40.08 g/mol + 2(16.00 g/mol + 1.01 g/mol) = 40.08 g/mol + 2(17.01 g/mol)= 74.1 g/mol\)
02

Calculate the Molar Mass of Oxygen in Calcium Hydroxide

Now determine the molar mass of the oxygen component. Note that there are two oxygen atoms in each molecule of calcium hydroxide: \(M_{O in Ca(OH)_{2}} = 2(16.00 g/mol) = 32.00 g/mol\)
03

Determine the Mass Proportion of Oxygen

Mass proportion of oxygen in calcium hydroxide is determined by dividing the molar mass of the oxygen component by the molar mass of the calcium hydroxide: Mass Proportion of Oxygen = \(\frac{M_{O in Ca(OH)_{2}}}{M_{Ca(OH)_{2}}} = \frac{32.00 g/mol}{74.1 g/mol} = 0.432\)
04

Activity the Mass Proportion of Oxygen

Compute the mass of oxygen in 148 grams of calcium hydroxide by multiplying the mass given by the proportion of oxygen: Mass of Oxygen = Mass Proportion of Oxygen * Mass of Calcium Hydroxide \(= 0.432 * 148 g = 63.93 g\)

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Most popular questions from this chapter

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