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Chapter 1: Problem 24

Which of the substances would be soluble in water? (A) Ethylene glycol only, because it has the longest bond lengths (B) Acetone only, because it is the most symmetrical (C) Ethanol and ethylene glycol only, because of their hydroxyl (-OH) (D) All three substances would be soluble in water due to their permanent dipoles.

Short Answer

Expert verified
D) All three substances, Ethanol, Ethylene glycol, and Acetone would be soluble in water due to their polar nature and the ability to interact with water molecules.

Step by step solution

01

Understand the molecular structure

It is vital to look at the molecular structures of the substances mentioned. Ethylene glycol and Ethanol both have hydroxyl (-OH) groups in their structures. Acetone does not have a hydroxyl group but is quite polar due to the presence of carbonyl (C=O) group.
02

Analyze the solubility principle

Solubility fundamentally depends on 'like dissolves like' principle, which means polar substances would be soluble in polar solvents like water. The hydroxyl (-OH) groups, because of their polarity, can form hydrogen bonds with water, thus making the substances soluble. Acetone is also polar due to the carbonyl group and can dissolve in water by forming dipole-dipole interactions.
03

Make the conclusion based on the analysis

Looking at the structures of Ethylene glycol, Ethanol, and Acetone and understanding the 'like dissolves like' principle, it is evident that all three substances would be soluble in water. Neither long bond lengths nor occurrence of symmetry directly influences the solubility of a substance in water.

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Most popular questions from this chapter

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