Questions 32-36 refer to the following. Two half-cells are set up as follows: Half-Cell A: Strip of \(\mathrm{Cu}(s)\) in \(\mathrm{CuNO}_{3}(a q)\) Half-Cell B: Strip of \(\mathrm{Zn}(s)\) in \(\mathrm{Zn}\left(\mathrm{NO}_{3}\right)_{2}\) (aq) When the cells are connected according to the diagram below, the following reaction occurs: GRAPH CAN'T COPY $$2 \mathrm{Cu}^{+}(a q)+\mathrm{Zn}(s) \rightarrow 2 \mathrm{Cu}(s)+\mathrm{Zn}^{2+}(a q) E^{\circ}=+1.28 \mathrm{V}$$ Correctly identify the anode and cathode in this reaction as well as where oxidation and reduction are taking place. (A) Cu is the anode where oxidation occurs, and Zn is the cathode where reduction occurs. (B) Cu is the anode where reduction occurs, and Zn is the cathode where oxidation occurs. (C) Zn is the anode where oxidation occurs, and Cu is the cathode where reduction occurs. (D) Zn is the anode where reduction occurs, and Cu is the cathode where oxidation occurs.

Short Answer

Expert verified
The Correct answer is (C): Zn is the anode where oxidation occurs, and Cu is the cathode where reduction occurs.

Step by step solution

01

Identification of Oxidation and Reduction

Oxidation and reduction reactions can be recognized from the given overall reaction. In the provided reaction: \(2 \mathrm{Cu}^{+}(a q)+\mathrm{Zn}(s) \rightarrow 2 \mathrm{Cu}(s)+\mathrm{Zn}^{2+}(a q)\), Cu+ is gaining an electron to become Cu (reduction) and Zn is losing two electrons to become Zn2+ (oxidation). 'Reduction' denotes that the element gains electrons, while 'oxidation' is when it loses electrons.
02

Assign Anode and Cathode

The anode and cathode can be assigned based on their activities in the electrochemical reaction. Oxidation occurs at the anode and reduction at the cathode. In this case, Zn (where oxidation occurs) is the anode and Cu+ (where reduction happens) is the cathode.

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Most popular questions from this chapter

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