Chapter 12: Problem 66
Which of these has the greatest density? (a) \(\mathrm{SF}_{6}\) at \(\mathrm{STP}\) (b) \(\mathrm{C}_{2} \mathrm{H}_{6}\) at room conditions (c) \(\mathrm{He}\) at \(-80^{\circ} \mathrm{C}\) and \(2.15\) atm
Short Answer
Expert verified
Using the Ideal Gas Law, \(\mathrm{SF}_{6}\) at STP has the greatest density because it has the largest molar mass and, at STP, occupies the same volume as \(\mathrm{C}_{2}\mathrm{H}_{6}\).
Step by step solution
01
Understand Density and its Relation to Conditions
Density is mass per unit volume. Standard conditions affect the volume of a gas due to Boyle's and Charles's Laws. Ampoules of gases at the same temperature and pressure will contain the same number of molecules due to Avogadro's Law but will have different masses because the molecules have different molecular weights. Standard Temperature and Pressure (STP) is defined as 0 degrees Celsius and 1 atm pressure.
02
Calculate Molar Masses
Calculate the molar masses of each substance: for \(\mathrm{SF}_{6}\) (Sulfur hexafluoride) it is 146.06 g/mol, for \(\mathrm{C}_{2}\mathrm{H}_{6}\) (Ethane) it is 30.07 g/mol, and for Helium (He) it is 4.00 g/mol.
03
Analyze the Conditions for Each Substance
For \(\mathrm{SF}_{6}\) at STP and \(\mathrm{C}_{2}\mathrm{H}_{6}\) at room conditions (approximately STP), 1 mol of each gas will occupy 22.4 liters. For Helium at -80 degrees Celsius and 2.15 atm, the volume can be calculated using the Ideal Gas Law, adjusting for the different temperature and pressure.
04
Ideal Gas Law for Helium
Using the Ideal Gas Law \(PV = nRT\), calculate the volume occupied by 1 mol of Helium. \(R = 0.0821 \mathrm{L\cdot atm/(mol\cdot K)}\), \(T = 193.15 \mathrm{K} (-80^\circ\mathrm{C} + 273.15)\), and \(P = 2.15 \mathrm{atm}\). Solve for \(V\) to find the volume at these conditions.
05
Calculate Densities
Density is calculated using the molar mass divided by the volume for 1 mol at the given conditions. \(\rho = \frac{m}{V}\). Calculate the density for each gas: \(\mathrm{SF}_{6}\) and \(\mathrm{C}_{2}\mathrm{H}_{6}\) at STP, and Helium at -80 degrees Celsius and 2.15 atm.
06
Compare Densities
With the molar mass and volume for each substance, compare their densities. The substance with the highest molar mass to volume ratio will have the greatest density.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
The Ideal Gas Law is a fundamental principle in chemistry that allows us to relate the pressure (\(P\text{, in atm}\)), volume (\(V\text{, in liters}\)), quantity of gas (\(n\text{, in moles}\)), and temperature (\(T\text{, in Kelvins}\)) of a gas sample. It is concisely represented by the equation:
\[PV = nRT\]
where \(R\) stands for the gas constant, having the value \(0.0821 \text{ L·atm/(mol·K)}\). To solve problems involving this law, we must ensure we're using the correct units: pressure in atmospheres, volume in liters, number of moles, and temperature in Kelvins.
For example, if we want to determine the volume occupied by helium (\(He\text{ gas}\)) at a certain temperature and pressure, we simply plug in our values into the Ideal Gas Law and solve for the volume. This law is crucial for the understanding of how gases behave under different conditions, and assists in making predictions about their properties, such as density, which can be calculated by dividing the gas’s molar mass by the volume it occupies.
\[PV = nRT\]
where \(R\) stands for the gas constant, having the value \(0.0821 \text{ L·atm/(mol·K)}\). To solve problems involving this law, we must ensure we're using the correct units: pressure in atmospheres, volume in liters, number of moles, and temperature in Kelvins.
For example, if we want to determine the volume occupied by helium (\(He\text{ gas}\)) at a certain temperature and pressure, we simply plug in our values into the Ideal Gas Law and solve for the volume. This law is crucial for the understanding of how gases behave under different conditions, and assists in making predictions about their properties, such as density, which can be calculated by dividing the gas’s molar mass by the volume it occupies.
Molar Mass
Molar mass is the weight of one mole of a chemical element or compound. It reflects the combined mass of all atoms in the molecule and is typically expressed in grams per mole (g/mol). The molar mass is critical in comparing the density of gases, as it provides the mass component in the density equation \(\rho = \frac{m}{V}\).
To calculate molar mass, add up the atomic masses of all atoms in the molecule. For example, sulfur hexafluoride (\(SF_6\text{ gas}\)) has a molar mass of 146.06 g/mol, calculated by summing the atomic masses of one sulfur and six fluorine atoms. Understanding molar mass allows us to determine how much of a particular gas can be found in a specific volume, a necessary step in comparing gas densities under various conditions.
To calculate molar mass, add up the atomic masses of all atoms in the molecule. For example, sulfur hexafluoride (\(SF_6\text{ gas}\)) has a molar mass of 146.06 g/mol, calculated by summing the atomic masses of one sulfur and six fluorine atoms. Understanding molar mass allows us to determine how much of a particular gas can be found in a specific volume, a necessary step in comparing gas densities under various conditions.
Standard Temperature and Pressure (STP)
Standard Temperature and Pressure (STP) are reference points used to report the properties of materials. By convention, STP is defined as a temperature of 0°C (273.15 K) and a pressure of 1 atmosphere (atm). At STP, one mole of an ideal gas occupies 22.4 liters, known as the molar volume of a gas.
The conditions of STP are essential for comparing the properties of different substances under consistent conditions. According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain the same number of particles (or moles). Consequently, if gases like \(SF_6\) and \(C_2H_6\) are both at STP, they will occupy the same volume despite their different molar masses. This makes STP a valuable comparison point when determining the density of gases, as it eliminates the volume variable from the density equation, thus allowing for a direct comparison based on molar mass alone.
The conditions of STP are essential for comparing the properties of different substances under consistent conditions. According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain the same number of particles (or moles). Consequently, if gases like \(SF_6\) and \(C_2H_6\) are both at STP, they will occupy the same volume despite their different molar masses. This makes STP a valuable comparison point when determining the density of gases, as it eliminates the volume variable from the density equation, thus allowing for a direct comparison based on molar mass alone.