Chapter 12: Problem 78
What pressure will 800 . \(\mathrm{mL}\) of a gas at \(\mathrm{STP}\) exert when its volume is \(250 . \mathrm{mL}\) at \(30^{\circ} \mathrm{C}\) ?
Short Answer
Expert verified
The final pressure is approximately 3.55 atm.
Step by step solution
01
- Identify the known variables at STP
The gas is initially at STP (Standard Temperature and Pressure). Standard Temperature is 0°C or 273.15 K, and Standard Pressure is 1 atm. The initial volume (\(V_1\)) is 800 mL.
02
- Identify the final conditions
The final volume (\(V_2\)) is given as 250 mL, and the final temperature (\(T_2\)) is 30°C or 303.15 K. We need to find the final pressure (\(P_2\)).
03
- Use the combined gas law
We will use the combined gas law formula: \[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \] This relates the pressure, volume, and temperature of the gas in two different states.
04
- Plug in the known values
Substitute the known values into the formula: \[ \frac{1 \text{ atm} \times 800 \text{ mL}}{273.15 \text{ K}} = \frac{P_2 \times 250 \text{ mL}}{303.15 \text{ K}} \]
05
- Solve for the final pressure
Isolate \(P_2\) by rearranging the equation: \[ P_2 = \frac{1 \text{ atm} \times 800 \text{ mL} \times 303.15 \text{ K}}{273.15 \text{ K} \times 250 \text{ mL}} \] Calculate the value step-by-step to find \(P_2\).
06
- Perform the calculation
Calculate the numerator and the denominator separately: \[ P_2 = \frac{800 \times 303.15}{273.15 \times 250} \] \[ = \frac{242520}{68287.5} \] Then perform the division to get the final result: \[ P_2 \approx 3.55 \text{ atm} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
The Ideal Gas Law
The ideal gas law is a fundamental principle in chemistry used to explain the relationship between pressure (P), volume (V), temperature (T), and the amount of gas (n) in moles. The law is usually expressed as: PV = nRT It incorporates the universal gas constant (R) and is helpful for solving problems where the amount of gas is constant but other variables change. Understanding the ideal gas law is crucial for grasping more complex gas behavior and advanced topics in physical chemistry. Alongside the combined gas law, the ideal gas law is essential in calculations involving gases. Ensure to consider the units: * Pressure (P) should be in atmospheres (atm), pascals (Pa), or any consistent unit. * Volume (V) typically in liters (L). * Temperature (T) in Kelvin (K). * R has a value of 0.0821 L·atm/mol·K when using atmospheres.
Understanding Gas Laws
Gas laws describe how gases behave under various conditions. They include Boyle's Law, Charles's Law, and Avogadro's Law. When integrated, they form the combined gas law and the ideal gas law. Boyle's Law states that the volume of a gas is inversely proportional to its pressure when the temperature is constant: PV = k Where k is a constant. Charles's Law shows a direct relationship between volume and temperature at constant pressure: V/T = k Avogadro's Law states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules: V/n = k By combining these laws, we arrive at: The Combined Gas Law: (P_1 V_1)/T_1 = (P_2 V_2)/T_2 This formula is especially useful when dealing with gas transitions between different states, as illustrated in our exercise. Familiarity with these laws enhances problem-solving skills in chemistry.
Steps for Effective Chemistry Problem Solving
Solving chemistry problems involves a systematic approach. Here are some steps that help: * Identify all given variables and what you need to find. * Convert units to ensure consistency, especially for temperature (use Kelvin). * Choose the appropriate gas law based on the problem's conditions. * Substitute known values into the equation. * Isolate the desired variable and solve algebraically. * Finally, calculate and check if the answer makes sense contextually. In our exercise, we knew the initial and final volumes and temperatures of the gas, and we needed to find the final pressure. By following the steps, we applied the combined gas law and found the final result through systematic calculation. Practice and familiarity with these steps will strengthen your problem-solving skills.
Temperature and Pressure Relationship
The relationship between temperature and pressure in gases is crucial in gas law problems. According to Gay-Lussac's Law, the pressure of a gas is directly proportional to its temperature when volume is held constant: P/T = k If temperature increases, the pressure will increase, provided the volume does not change. This relationship is embedded within the combined gas law used in the exercise: (P_1 V_1)/T_1 = (P_2 V_2)/T_2 As in the exercise, understanding how changing temperature affects pressure—while also considering volume changes—is foundational for predicting gas behavior. Make sure to convert temperatures to Kelvin for accurate calculations, as Celsius does not measure absolute temperature change in the gas laws.