Acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) and hydrogen fluoride (HF) react to give difluoroethane: $$ \mathrm{C}_{2} \mathrm{H}_{2}(g)+2 \mathrm{HF}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{~F}_{2}(g) $$ When \(1.0 \mathrm{~mol}\) of \(\mathrm{C}_{2} \mathrm{H}_{2}\) and \(5.0 \mathrm{~mol}\) of \(\mathrm{HF}\) are reacted in a 10.0-L flask, what will be the pressure in the flask at \(0^{\circ} \mathrm{C}\) when the reaction is complete?

Short Answer

Expert verified
The pressure in the flask at 0°C is approximately 8.98 atm.

Step by step solution

01

Use the Ideal Gas Law

The ideal gas law is given by the equation: \[ PV = nRT \]. This will help to find the pressure when the reaction is complete.
02

Calculate total moles of reactants initially

Initially, the total moles of gas is the sum of the moles of acetylene and hydrogen fluoride. Given: \[ n_{\text{initial}} = n_{\text{acetylene}} + n_{\text{HF}} = 1.0 \text{ mol} + 5.0 \text{ mol} = 6.0 \text{ mol} \]
03

Determine the Limiting Reactant

To determine which reactant is limiting, use the stoichiometric coefficients: 1 mol of \( \mathrm{C}_2\mathrm{H}_2\) reacts with 2 mols of \( \mathrm{HF} \).Given 1 mol of \( \mathrm{C}_2\mathrm{H}_2 \), it requires \( 2 \times 1 = 2 \text{ mols of } \mathrm{HF} \).Since we have 5 mols of \( \mathrm{HF} \), acetylene is the limiting reactant.
04

Calculate the moles of products formed and excess reactant left

Since \( \mathrm{C}_{2}\mathrm{H}_2 \) is the limiting reactant, it will be completely consumed. The reaction consumes 2 moles of \( \mathrm{HF} \) for every 1 mole of \( \mathrm{C}_{2}\mathrm{H}_2 \), so 2 moles of HF are used. Moles of \( \mathrm{C}_{2}\mathrm{H}_{4}\mathrm{F}_2 \) formed: 1 mol Moles of HF left: \( 5 - 1 \times 2 = 3 \) mol Total moles after reaction: \( 1 + 3 = 4 \text{ mols} \).
05

Apply the Ideal Gas Law

Using the ideal gas law \[ PV = nRT \], where: \( P \) is the pressure, \( V = 10.0\text{ L} \), \( n = 4\text{ mols} \), \( R = 0.0821\frac{L\text{atm}}{K\text{mol}} \), \( T = 273K \). Rewriting it for pressure: \[ P = \frac{nRT}{V} = \frac{(4\text{ mols})(0.0821 \frac{L\text{atm}}{K\text{mol}})(273K)}{(10.0 \text{ L})} \approx 8.98 \text{ atm} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is the calculation of reactants and products in chemical reactions. It is based on the balanced chemical equation, which shows the relationship between the quantities of reactants and products. To solve stoichiometry problems, follow these steps:
  • Balance the chemical equation to get the correct ratio of reactants to products.
  • Convert quantities of known substances into moles (using molar masses if necessary).
  • Use the balanced equation to set up mole ratios and solve for the unknown quantities.
In our example, the balanced equation is: \[ \mathrm{C}_{2} \mathrm{H}_{2}(g)+2 \mathrm{HF}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{~F}_{2}(g) \] This tells us that 1 mole of \(\mathrm{C}_{2}\mathrm{H}_{2} \) reacts with 2 moles of \(\mathrm{HF}\) to produce 1 mole of \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{~F}_{2} \). Make sure to use these coefficients in calculations.
Limiting Reactant
In chemical reactions, the limiting reactant is the substance that is completely consumed first, limiting the amount of product that can be formed. To identify the limiting reactant:
  • Calculate the moles of each reactant available.
  • Use the stoichiometric coefficients to determine how much of each reactant is needed to react completely.
  • Compare the amount needed to the amount available to see which reactant will run out first.
In the provided exercise, we determined that 1 mole of \(\mathrm{C}_{2} \mathrm{H}_{2} \) reacts with 2 moles of \(\mathrm{HF} \). Given 1 mole of \(\mathrm{C}_{2} \mathrm{H}_{2} \) and 5 moles of \(\mathrm{HF} \), the acetylene is the limiting reactant because it requires only 2 moles of HF for complete reaction, and we have more than enough HF.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry that describes the behavior of ideal gases. It is written as: \[ PV = nRT \]
  • \(P \) is the pressure of the gas.
  • \(V \) is the volume of the gas.
  • \(n \) is the number of moles of the gas.
  • \(R \) is the ideal gas constant \(0.0821 \frac{L\text{atm}}{K\text{mol}} \).
  • \(T \) is the temperature in Kelvin.
To find the pressure when the reaction is complete, we substitute the values into the Ideal Gas Law equation. For the given problem, the volume is 10.0 L, the total moles of gas is 4, the temperature is 0°C (which is 273 K), and the gas constant is \(0.0821 \frac{L\text{atm}}{K\text{mol}} \). Rewriting the equation for pressure: \[ P = \frac{nRT}{V} = \frac{(4 \text{ mols})(0.0821 \frac{L\text{atm}}{K\text{mol}})(273K)}{(10.0 \text{ L})} \approx 8.98 \text{ atm} \] So, the pressure in the flask when the reaction is complete is approximately 8.98 atm.
Chemical Reactions
A chemical reaction involves the transformation of reactants into products. Indicators of a chemical reaction include color change, temperature change, gas production, and precipitate formation. To understand chemical reactions, keep these points in mind:
  • Reactants are substances that start a reaction, while products are substances that are produced.
  • A balanced chemical equation follows the law of conservation of mass, meaning the number of atoms of each element must be the same on both sides.
  • Chemists use balanced equations to predict the amounts of products and reactants involved.
In our example, the equation shows the reactants \(\mathrm{C}_{2} \mathrm{H}_{2} \) and \(\mathrm{HF} \), while \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{~F}_{2} \) is the product. The balanced equation ensures that the same amount of each atom is present before and after the reaction.
Gas Pressure
Gas pressure is the force exerted by gas molecules when they collide with the walls of their container. It is influenced by several factors:
  • Number of gas molecules: More molecules result in higher pressure.
  • Temperature: Higher temperatures increase the kinetic energy of molecules, leading to more frequent collisions and higher pressure.
  • Volume of the container: A smaller volume leads to more collisions and higher pressure.
The Ideal Gas Law \(PV = nRT \) connects these factors to calculate gas pressure. For example, in the exercise, we calculated the pressure to be approximately 8.98 atm after completing the reaction by considering the total moles of gas, the temperature, and the volume of the container.

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