Chapter 14: Problem 18
Calculate the molarity of the following solutions: (a) \(0.50 \mathrm{~mol}\) of solute in \(125 \mathrm{~mL}\) of solution (b) \(2.25 \mathrm{~mol}\) of \(\mathrm{CaCl}_{2}\) in \(1.50 \mathrm{~L}\) of solution (c) \(275 \mathrm{~g} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) in \(775 \mathrm{~mL}\) of solution (d) \(125 \mathrm{~g} \mathrm{MgSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) in \(2.50 \mathrm{~L}\) of solution
Short Answer
Step by step solution
- Understanding Molarity
- Calculate Molarity for Part (a)
- Calculate Molarity for Part (b)
- Calculate Molarity for Part (c)
- Calculate Molarity for Part (d)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molarity
- Identify the moles of solute in your solution.
- Measure the volume of your solution in liters.
- Use the formula to calculate the molarity.
Converting Units in Chemistry
- Milliliters to Liters: Divide by 1000. For example, 125 mL is converted to 0.125 L.
- Grams to Moles: Use the compound's molar mass (found on the periodic table). For instance, if you have 275 g of glucose (C₆H₁₂O₆), you need its molar mass (180.16 g/mol) to convert it to moles: \[ \text{Moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{275 \text{ g}}{180.16 \text{ g/mol}} \approx 1.526 \text{ mol} \]
Solution Concentration Calculation
- Identify the solute (the substance being dissolved).
- Determine the number of moles of solute.
- Measure the volume of the solution (the solute + solvent) in liters.
- Use the molarity formula to find the concentration.
Moles and Volume Relationship
- Adding more solute increases molarity.
- Increasing volume decreases molarity.