Gingerone, a molecule found in ginger, is converted to zingerone by cooking. This is the molecule that contributes the flavor to foods cooked with ginger. You are perfecting the recipe for your punch and have discovered that to achieve the perfect flavor you need to have a final concentration of zingerone of \(6.05 \times 10^{-5} M\). How much of a \(1.15 \times 10^{-3} M\) solution of zingerone do you need to make \(10.0\) liters of punch?

Short Answer

Expert verified
You need 0.526 liters (or 526 mL) of the concentrated zingerone solution to make 10.0 liters of punch with the desired flavor.

Step by step solution

01

Understand the Dilution Concept

To find out how much of the concentrated zingerone solution is needed, use the dilution formula, which is: \( C_1V_1 = C_2V_2 \), where \( C_1 \) and \( V_1 \) are the concentration and volume of the more concentrated solution, respectively, and \( C_2 \) and \( V_2 \) are the concentration and volume of the diluted solution.
02

Identify Known Variables

For the given problem, we have the final concentration \( C_2 = 6.05 \times 10^{-5} M \), and the final volume \( V_2 = 10.0 \) liters of the punch. The initial concentration of the zingerone solution is \( C_1 = 1.15 \times 10^{-3} M \). We need to find the initial volume \( V_1 \).
03

Rearrange the Dilution Formula

We rearrange the dilution formula to solve for \( V_1 \): \( V_1 = \frac{C_2V_2}{C_1} \).
04

Substitute Known Values and Solve for \( V_1 \)

\( V_1 = \frac{6.05 \times 10^{-5} M \times 10.0 \text{ liters}}{1.15 \times 10^{-3} M} = \frac{6.05 \times 10^{-4} M \cdot L}{1.15 \times 10^{-3} M} \). Now perform the division to find \( V_1 \).
05

Calculate the Required Amount of Zingerone Solution

\( V_1 = \frac{6.05 \times 10^{-4}}{1.15 \times 10^{-3}} = 0.526 \) liters. This is the amount of concentrated zingerone solution needed to make the punch with the perfect flavor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molarity Calculation
Understanding molarity is crucial in chemistry, particularly when mixing solutions for desired concentrations. Molarity, represented by the symbol 'M', is a measure of the concentration of a solution, defined as the number of moles of solute per liter of solution. The formula to calculate molarity is expressed as:
\[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \].
In the context of the provided exercise, molarity calculation helps in determining how much of a concentrated zingerone solution to use. Given a requirement for a specific molarity in the final solution, we reverse-engineer the process to figure out the starting volume of the concentrated solution needed. By rearranging the molarity formula and applying it to both the initial concentrated solution and the final diluted solution, we can find the relationships between their volumes and concentrations.
Solution Preparation
The process of preparing a solution with a desired concentration involves careful calculation and measurement. In practice, this is often done by diluting a more concentrated stock solution. By using the dilution formula \( C_1V_1 = C_2V_2 \), we can determine the volume of stock solution needed. This formula reflects the fact that the amount of solute remains constant before and after dilution, hence the product of concentration and volume must remain the same. To prepare the diluted solution:
  • Measure the calculated volume (\( V_1 \)) of the concentrated solution.
  • Transfer this volume into a new container that can hold the final total volume of the solution (\( V_2 \)).
  • Add enough solvent to the concentrated solution until the final volume is reached.
  • Mix the solution thoroughly to evenly distribute the solute.
By following these steps, one ensures a uniform solution with the desired molarity.
Concentration and Volume Relationship
The dilution formula \( C_1V_1 = C_2V_2 \), which explains the concentration and volume relationship, is central to finding the amount of solution needed for dilutions. Here's how it works:
  • \( C_1 \) is the initial concentration of the solution before dilution.
  • \( V_1 \) is the volume of the concentrated solution you need to find or measure.
  • \( C_2 \) is the concentration after dilution, often the desired concentration for your purposes.
  • \( V_2 \) is the final volume of the solution after dilution, which you often know beforehand.
The product of the initial concentration and volume equals the product of the final concentration and volume because the amount of solute in the solution remains unchanged during dilution. Changing the volume of solvent affects the concentration of the solution inversely. This relationship is critical in many applications, such as cooking, pharmaceuticals, and chemical experiments, where specific concentrations must be achieved.

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