Law enforcement uses a quick and easy test for the presence of the illicit drug \(\mathrm{PCP}\), reacting it with potassium iodide. The PCP will form a crystalline solid with a long branching needlelike structure with \(\mathrm{Kl}\). What is the molarity of \(\mathrm{Kl}\) in a stock solution prepared by dissolving \(396.1 \mathrm{~g}\) of \(\mathrm{Kl}\) to a total volume of \(750.0 \mathrm{~mL}\) ?

Short Answer

Expert verified
The molarity of the KI solution is approximately 2.39 M.

Step by step solution

01

Find the molar mass of Potassium Iodide (KI)

Calculate the molar mass of KI by adding the atomic masses of potassium (K) and iodine (I). The atomic mass of K is approximately 39.1 g/mol, and the atomic mass of I is approximately 126.9 g/mol. Thus, the molar mass of KI is 39.1 + 126.9 = 166.0 g/mol.
02

Calculate the number of moles of KI

Using the molar mass of KI, calculate the number of moles of KI present in the 396.1 g sample by the formula: number of moles = mass (g) / molar mass (g/mol). This would be 396.1 g / 166.0 g/mol.
03

Convert the volume from mL to liters

Since molarity is defined as moles per liter, convert the volume of the solution from mL to liters by dividing by 1000. Thus, 750.0 mL is 0.7500 liters.
04

Calculate the molarity of the KI solution

Divide the number of moles of KI by the volume of the solution in liters to find the molarity using the formula: molarity (M) = moles of solute / liters of solution. This will be the molarity of the KI stock solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is a section of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. When solving stoichiometry problems, we start by looking at the balanced chemical equation to understand the mole ratio between substances involved. Then, using this ratio, we can perform calculations to find out how much of a substance is needed or produced.

Improving your stoichiometry skills will not only help with simple molarity calculations but also enable you to predict the outcomes of reactions accurately, and understand how to scale up from a laboratory to an industrial scale if needed.
Molecular Weight
The molecular weight, also known as molecular mass or molar mass, is the weight of one mole of a substance, typically expressed in grams per mole (g/mol). It's calculated by adding the atomic masses of all the atoms in the molecule. For instance, the molecular weight of potassium iodide (KI) involves the weights of potassium and iodine. Knowing the molecular weight is essential for converting between grams of a substance and moles, a step that is crucial in many chemical calculations.

Determining the molecular weight accurately affects the accuracy of your stoichiometry calculations and helps in achieving the desired concentration of a chemical solution.
Mole Calculation
The mole calculation is an essential skill in chemistry that allows you to determine the number of moles in a given sample. The formula is straightforward: number of moles = mass of sample (g) / molar mass (g/mol). By mastering this calculation, you can easily relate the grams of a substance to its chemical equivalence in moles, which is fundamental when preparing solutions, as seen in the exercise on determining the molarity of a potassium iodide solution.

This calculation is the bridge between the tangible mass of a substance and the amount of that substance needed for a chemical reaction, as defined by the balanced equation. Hence, the accuracy of mole calculations directly impacts the success of a reaction or the preparation of a solution with the correct concentration.
Chemical Solution Concentration
The concentration of a chemical solution tells you how much solute is present compared to the solvent. Molarity, one measure of concentration, is the number of moles of solute per liter of solution. To calculate molarity, you'll first need to perform a mole calculation, as demonstrated in the solution steps for the potassium iodide exercise.

Understanding how to calculate and prepare solutions with precise concentrations is vital in many branches of chemistry, from chemical synthesis and analysis to pharmacology and environmental science. It ensures that experimental conditions are consistent and that chemical reactions occur as intended.

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Most popular questions from this chapter

Which would be more effective as an antifreeze in an automobile radiator? A solution containing (a) \(10 \mathrm{~kg}\) of methyl alcohol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) or \(10 \mathrm{~kg}\) of ethyl alcohol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right) ?\) (b) \(10 \mathrm{~m}\) solution of methyl alcohol or \(10 \mathrm{~m}\) solution of ethyl alcohol?

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A pot of chai tea has a volume of 600 . \(\mathrm{mL}\), a mass of 618 . \(\mathrm{g}\), and contains \(866 \mathrm{mg}\) of cinnamaldehyde \(\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}\right)\), the principal component of cinnamon. (a) What is the molarity of cinnamaldehyde in the tea? (b) What is the mass percent of cinnamaldehyde in the tea? (c) What is the mass/volume percent of cinnamaldehyde in the tea?

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