Chapter 14: Problem 89
How would you prepare a \(6.00 M \mathrm{HNO}_{3}\) solution if only \(3.00 \mathrm{M}\) and \(12.0 \mathrm{M}\) solutions of the acid are available for mixing?
Short Answer
Expert verified
Mix the two solutions in a 2:1 volume ratio of the 3.00 M to the 12.0 M solution to achieve the final concentration of 6.00 M HNO3. That is, for every 2 volumes of the 3.00 M solution, use 1 volume of the 12.0 M solution.
Step by step solution
01
Identify the target concentration desired
We want to prepare a solution with a concentration of 6.00 M of \(\mathrm{HNO}_{3}\). This is the target concentration for the final solution.
02
Apply the principle of mixtures
We use the equation \(C_1V_1 + C_2V_2 = C_fV_f\), where \(C_1\) and \(C_2\) are the concentrations of the original solutions, \(V_1\) and \(V_2\) are the volumes of the original solutions that will be mixed, and \(C_f\) and \(V_f\) are the concentration and volume of the final solution respectively. In this case, \(C_1 = 3.00\ M\), \(C_2 = 12.0\ M\), and \(C_f = 6.00\ M\). We want to find values for \(V_1\) and \(V_2\).
03
Set up the equation for the final volume
Assuming we want to create \(V_f\) liters of the final solution, the equation becomes \(3.00\mathrm{M} \times V_1 + 12.0\mathrm{M} \times V_2 = 6.00\mathrm{M} \times V_f\).
04
Derive a relationship between \(V_1\) and \(V_2\)
To simplify the calculation, we can express one variable in terms of the other. Because the volumes are additive, we can state \(V_1 + V_2 = V_f\). For every volume part of the 12.0 M solution used, we need to use an equal total volume part minus the volume of the 12.0 M solution part of the 3.00 M to keep the volume consistent. We can then express \(V_2\) as \(V_f - V_1\).
05
Substitute \(V_2\) in the initial equation and solve for \(V_1\)
Substituting the expression for \(V_2\) into the equation from Step 3, we get \(3.00\mathrm{M} \times V_1 + 12.0\mathrm{M} \times (V_f - V_1) = 6.00\mathrm{M} \times V_f\). Rearrange and solve this equation to find the relationship between \(V_1\) and \(V_f\).
06
Calculate the final volumes of each solution
After simplifying the equation, we can find a specific ratio in which to mix the volumes of the two original solutions to achieve the desired concentration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Concentration of Solutions
Understanding the concentration of solutions is a cornerstone in chemistry, especially when preparing a specific solution from different concentrations. The concentration of a solution is a measure of the amount of solute that is dissolved in a given quantity of solvent or solution. Imagine if you have a glass of lemonade: the sugar and lemon juice mixed with the water determine the concentration - more sugar means a sweeter (more concentrated) drink.
When a student encounters a problem related to preparing solutions, knowing the concentration concept is crucial. Concentration can be expressed in various ways, such as molarity, molality, or parts per million (ppm), with molarity being the most commonly used in academic settings. By adjusting the concentration, students can learn to control reactions and understand their mechanisms, which is a valuable skill in laboratory and industrial settings.
When a student encounters a problem related to preparing solutions, knowing the concentration concept is crucial. Concentration can be expressed in various ways, such as molarity, molality, or parts per million (ppm), with molarity being the most commonly used in academic settings. By adjusting the concentration, students can learn to control reactions and understand their mechanisms, which is a valuable skill in laboratory and industrial settings.
Molarity
Molarity is a term that comes up frequently in chemistry and is symbolized by 'M'. It's defined as the number of moles of solute per liter of solution. The moles of a substance are a measurement of particles, often molecules or atoms. If you have a 1.00 M sugar solution, this means you have 1 mole of sugar dissolved in 1 liter of water. It's like saying you have a certain number of sugar packets per jug of water — a way of quantifying the 'strength' of your solution.
To calculate molarity, you use the formula:
\( M = \frac{{moles\text{{ of solute}}}}{{volume\text{{ of solution in liters}}}} \). This formula embodies the heart of preparing solutions in chemistry, allowing students to calculate the exact amount to mix to achieve a desired concentration. Remember, accurate measurements are key to getting reliable results in any experiment!
To calculate molarity, you use the formula:
\( M = \frac{{moles\text{{ of solute}}}}{{volume\text{{ of solution in liters}}}} \). This formula embodies the heart of preparing solutions in chemistry, allowing students to calculate the exact amount to mix to achieve a desired concentration. Remember, accurate measurements are key to getting reliable results in any experiment!
Principle of Mixtures
The principle of mixtures plays a crucial role when combining two solutions to achieve a target molarity. It's based on the concept that when you combine solutions, their volumes are additive, and the amount of substance in the combined volume is the sum from each original solution.