Chapter 15: Problem 42
Calculate the \(\mathrm{pH}\) of (a) black coffee, \(5.0 \times 10^{-5} \mathrm{MH}^{+}\) (b) limewater, \(3.4 \times 10^{-11} \mathrm{M} \mathrm{H}^{+}\) (c) fruit punch, \(2.1 \times 10^{-4} \mathrm{MH}^{+}\) (d) cranberry apple drink, \(1.3 \times 10^{-3} \mathrm{M} \mathrm{H}^{+}\)
Short Answer
Expert verified
The \(\text{pH}\) values are: (a) 4.301, (b) 10.4685, (c) 3.6778, (d) 2.8861.
Step by step solution
01
- Understanding the formula for \(\text{pH}\)
The \(\text{pH}\) is calculated using the formula: \(\text{pH} = -\text{log}[\text{H}^+]\), where \([\text{H}^+]\) is the concentration of hydrogen ions.
02
- Calculate the \(\text{pH}\) of black coffee
Given: \([\text{H}^+] = 5.0 \times 10^{-5} \)M. Use the formula: \(\text{pH} = -\text{log}(5.0 \times 10^{-5})\). Calculate the logarithm to find: \(\text{pH} = -\text{log}(5.0) - \text{log}(10^{-5}) = -0.6990 + 5 = 4.301\).
03
- Calculate the \(\text{pH}\) of limewater
Given: \([\text{H}^+] = 3.4 \times 10^{-11} \)M. Use the formula: \(\text{pH} = -\text{log}(3.4 \times 10^{-11})\). Calculate the logarithm to find: \(\text{pH} = -\text{log}(3.4) - \text{log}(10^{-11}) = -0.5315 + 11 = 10.4685\).
04
- Calculate the \(\text{pH}\) of fruit punch
Given: \([\text{H}^+] = 2.1 \times 10^{-4} \)M. Use the formula: \(\text{pH} = -\text{log}(2.1 \times 10^{-4})\). Calculate the logarithm to find: \(\text{pH} = -\text{log}(2.1) - \text{log}(10^{-4}) = -0.3222 + 4 = 3.6778\).
05
- Calculate the \(\text{pH}\) of cranberry apple drink
Given: \([\text{H}^+] = 1.3 \times 10^{-3} \)M. Use the formula: \(\text{pH} = -\text{log}(1.3 \times 10^{-3})\). Calculate the logarithm to find: \(\text{pH} = -\text{log}(1.3) - \text{log}(10^{-3}) = -0.1139 + 3 = 2.8861\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
acid-base chemistry
Understanding acid-base chemistry is fundamental for calculating the \(\text{pH}\) of solutions. This branch of chemistry studies the properties of acids and bases and their reactions with each other. An acid is a substance that donates hydrogen ions (\(\text{H}^+\)) in a solution, while a base accepts them. Key concepts within acid-base chemistry include the strength of acids and bases, and the concept of conjugate acid-base pairs.
The \(\text{pH}\) of a solution is a measure of its acidity or basicity. A lower \(\text{pH}\) indicates an acidic solution, and a higher \(\text{pH}\) indicates a basic or alkaline solution. Neutral solutions have a \(\text{pH}\) of around 7.
The \(\text{pH}\) of a solution is a measure of its acidity or basicity. A lower \(\text{pH}\) indicates an acidic solution, and a higher \(\text{pH}\) indicates a basic or alkaline solution. Neutral solutions have a \(\text{pH}\) of around 7.
- Acidic: \(\text{pH} < 7\)
- Neutral: \(\text{pH} = 7\)
- Basic: \(\text{pH} > 7\)
logarithms
Logarithms are mathematical functions that are essential for understanding \(\text{pH}\) calculations. The logarithm of a number is the power to which a given base must be raised to produce that number. In \(\text{pH}\) calculations, we use the base 10 logarithm, often written as \(-\text{log}(x)\).
The \(\text{pH}\) formula: \(\text{pH} = -\log[\text{H}^+]\), means we take the negative logarithm of the hydrogen ion concentration.
To calculate logarithms, use the following steps: \[-\text{log}(a \times 10^b) = -\text{log}(a) - \text{log}(10^b) = -\text{log}(a) + (-b)\] For example, for black coffee: \( \text{pH} = -\log(5.0 \times 10^{-5}) = -\log(5.0) - (-5) = -0.6990 + 5 = 4.301\).
Logarithms simplify complex multiplications and divisions involving large numbers by transforming them into easier additions and subtractions.
The \(\text{pH}\) formula: \(\text{pH} = -\log[\text{H}^+]\), means we take the negative logarithm of the hydrogen ion concentration.
To calculate logarithms, use the following steps: \[-\text{log}(a \times 10^b) = -\text{log}(a) - \text{log}(10^b) = -\text{log}(a) + (-b)\] For example, for black coffee: \( \text{pH} = -\log(5.0 \times 10^{-5}) = -\log(5.0) - (-5) = -0.6990 + 5 = 4.301\).
Logarithms simplify complex multiplications and divisions involving large numbers by transforming them into easier additions and subtractions.
hydrogen ion concentration
Hydrogen ion concentration, represented as \(\text{H}^+\) or \([\text{H}^+]\), is a crucial part of calculating \(\text{pH}\). It's a measure of the amount of hydrogen ions present in a solution.
High \(\text{H}^+\) concentration means the solution is more acidic, while low \(\text{H}^+\) concentration indicates a more basic or alkaline solution. This concentration is usually expressed in moles per liter (M).
In practice, when provided with \(\text{H}^+\) concentration:
High \(\text{H}^+\) concentration means the solution is more acidic, while low \(\text{H}^+\) concentration indicates a more basic or alkaline solution. This concentration is usually expressed in moles per liter (M).
In practice, when provided with \(\text{H}^+\) concentration:
- If \(\text{H}^+ = 1 \times 10^{-3} \text{M}, then \text{pH} = 3\)
- If \(\text{H}^+ = 1 \times 10^{-7} \text{M}, then \text{pH} = 7\)
solution acidity
Solution acidity refers to how acidic a solution is, based on its \(\text{pH}\). The term 'acidity' encompasses the concentration of hydrogen ions within a solution. A more acidic solution has a higher concentration of \(\text{H}^+\), resulting in a lower \(\text{pH}\).
Different solutions have varying levels of acidity:
Different solutions have varying levels of acidity:
- Black coffee: \(\text{H}^+ = 5.0 \times 10^{-5} \text{M}, \text{pH} = 4.301\)
- Limewater: \(\text{H}^+ = 3.4 \times 10^{-11} \text{M}, \text{pH} = 10.4685\)
- Fruit punch: \(\text{H}^+ = 2.1 \times 10^{-4} \text{M}, \text{pH} = 3.6778\)
- Cranberry apple drink: \(\text{H}^+ = 1.3 \times 10^{-3} \text{M}, \text{pH} = 2.8861\)