Chapter 19: Problem 76
Which of these compounds are structural isomers of each other? methyl propyl ether, butanoic acid, acetone, propene, 2 -butanol, phenol, methyl propanoate
Short Answer
Expert verified
Methyl propyl ether and 2-Butanol, Butanoic acid and Methyl propanoate are structural isomers.
Step by step solution
01
- Identify the molecular formulas
Determine the molecular formulas for each compound. Methyl propyl ether: C4H10O, Butanoic acid: C4H8O2, Acetone: C3H6O, Propene: C3H6, 2-Butanol: C4H10O, Phenol: C6H6O, Methyl propanoate: C4H8O2.
02
- Group compounds with the same molecular formula
Comparing the molecular formulas from Step 1: Methyl propyl ether (C4H10O) and 2-Butanol (C4H10O) are grouped together. Butanoic acid (C4H8O2) and Methyl propanoate (C4H8O2) are grouped together. Acetone (C3H6O) and Propene (C3H6) have no match. Phenol (C6H6O) has no match.
03
- Confirm structural isomers
Methyl propyl ether and 2-Butanol, both with the formula C4H10O, have different structures. Butanoic acid and Methyl propanoate, both with the formula C4H8O2, also have different structures. Therefore, these pairs are structural isomers.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Formulas
Molecular formulas provide the total number of each type of atom in a molecule. For instance, the molecular formula C4H10O means the molecule contains 4 carbon atoms, 10 hydrogen atoms, and 1 oxygen atom. It is crucial to identify and compare molecular formulas when dealing with structural isomers in organic chemistry. This method aids in grouping compounds with identical atom counts and sets us up for more in-depth structural analysis. By taking the initial step of identifying molecular formulas, we can quickly recognize potential structural isomers.
For example, here are the formulas we determined in our exercise:
For example, here are the formulas we determined in our exercise:
- Methyl propyl ether: C4H10O
- Butanoic acid: C4H8O2
- Acetone: C3H6O
- Propene: C3H6
- 2-Butanol: C4H10O
- Phenol: C6H6O
- Methyl propanoate: C4H8O2
Isomer Identification
Isomers are compounds that have the same molecular formula but different structures. This primary concept in organic chemistry explains why two substances with the same number of each type of atom can have vastly different properties. Structural isomers, in particular, are molecules that differ in the connectivity of their atoms.
To identify isomers, follow these steps:
1. Start by grouping compounds with the same molecular formula.
2. Compare the arrangement of atoms within these groups.
For example, in our exercise, we identified the following pairs of structural isomers:
To identify isomers, follow these steps:
1. Start by grouping compounds with the same molecular formula.
2. Compare the arrangement of atoms within these groups.
For example, in our exercise, we identified the following pairs of structural isomers:
- Methyl propyl ether and 2-Butanol (both C4H10O)
- Butanoic acid and Methyl propanoate (both C4H8O2)
Functional Groups
Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. Recognizing functional groups is essential for identifying the type and reactivity of an organic compound. Here are some functional groups involved in our exercise:
- Ethers (e.g., Methyl propyl ether)
- Carboxylic acids (e.g., Butanoic acid)
- Alcohols (e.g., 2-Butanol and Phenol)
- Esters (e.g., Methyl propanoate)
Organic Compounds
Organic compounds are vast and varied, primarily composed of carbon atoms bonded with hydrogen, oxygen, nitrogen, and other elements. They are the basis of all known life and countless materials we use daily. The main types identified in our exercise include:
- Ethers (e.g., Methyl propyl ether)
- Carboxylic acids (e.g., Butanoic acid)
- Alcohols (e.g., 2-Butanol)
- Esters (e.g., Methyl propanoate)
- Ketones (e.g., Acetone)
- Alkenes (e.g., Propene)
- Aromatic compounds (e.g., Phenol)