One molecule of an unknown compound is found to have a mass of \(3.27 \times 10^{-22} \mathrm{~g}\). What is the molar mass of this compound?

Short Answer

Expert verified
The molar mass is 19.7 g/mol.

Step by step solution

01

- Determine Avogadro's Number

Avogadro's number is the number of constituent particles (usually atoms or molecules) that are contained in one mole of a substance. It is a constant value: \[N_A = 6.022 \times 10^{23} \text{ particles/mol} \]
02

- Convert Mass of One Molecule to Mass Per Mole

To find the molar mass, multiply the mass of a single molecule of the compound by Avogadro's number: \[ \text{Molar Mass (g/mol)} = 3.27 \times 10^{-22} \text{ g/molecule} \times 6.022 \times 10^{23} \text{ molecules/mol} \]
03

- Perform the Calculation

Calculate the product of the given mass of one molecule and Avogadro's number: \[ \text{Molar Mass} = 3.27 \times 6.022 \times 10^{1} \text{ g/mol} \] Then, \[ \text{Molar Mass} \rightarrow 3.27 \times 6.022 \times 10 = 19.6934 \text{ g/mol} \]
04

- Round to Appropriate Significant Figures

Given the precision of the initial data (3 significant figures), round the final answer accordingly: \[ \text{Molar Mass} \rightarrow 19.7 \text{ g/mol} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's Number
Avogadro's number is a fundamental constant in chemistry and is essential for understanding the relationship between individual molecules and moles of a substance. It is denoted as \(N_A\) and its value is \6.022 \times 10^{23}\ particles/mol. This constant allows us to convert between the number of atoms or molecules in a single sample and the macroscopic quantities we handle in the lab. For example, since one mole of any substance contains Avogadro's number of molecules, if we know the mass of a single molecule, we can calculate the molar mass by multiplying the mass of one molecule by Avogadro's number. This provides a bridge between the microscopic world of individual atoms and molecules and the macroscopic quantities used in chemical calculations.
Mass Conversion
Mass conversion is a crucial step in chemistry when dealing with different units or scales. In this context, we are converting the mass of a single molecule to the mass of an entire mole of molecules. This is done by multiplying the mass of one molecule by Avogadro's number. For example, given the mass of one molecule \(3.27 \times 10^{-22} \mathrm{g}\) and Avogadro's number \6.022 \times 10^{23}\, we perform the multiplication:

\[ \text{Molar Mass (g/mol)} = 3.27 \times 10^{-22} \text{ g/molecule} \times 6.022 \times 10^{23} \text{ molecules/mol} \]. This step is critical as it translates molecular-scale measurement into a more practical macroscopic scale used in the laboratory.
Significant Figures
When performing calculations, it's important to consider significant figures. Significant figures indicate the precision of a measurement. In our example, we initially have three significant figures (3.27). Upon calculating the molar mass, we maintain this precision: \( 3.27 \times 6.022 \times 10 = 19.7 \ g/mol\). By rounding to three significant figures, which matches the precision of our least precise measurement, we ensure our answer is as accurate as the initial data allows. Always round your final answer according to the number of significant figures in the initial data to maintain consistency and accuracy in scientific communication. This concept ensures reliability and standardization across scientific calculations and reporting.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A substance whose formula is \(\mathrm{A}_{2} \mathrm{O}\) (A is a mystery element) is \(60.0 \% \mathrm{~A}\) and \(40.0 \% \mathrm{O}\). Identify the element \(\mathrm{A}\).

Receptor proteins that allow us to sense heat have been isolated as well as molecules that cause us to perceive heat such as hot pepper and wasabi. If such proteins are able to detect as little as \(20.0 \mu \mathrm{g}\) of capsaicin, the chemical responsible for the burn in peppers, how many molecules of capsaicin \(\left(\mathrm{C}_{18} \mathrm{H}_{27} \mathrm{NO}_{3}\right)\) are required before the tongue can detect it?

A 73.16-g sample of an interesting barium silicide reported to have superconducting properties was found to contain \(33.62 \mathrm{~g}\) barium and the remainder silicon. Calculate the percent composition of the compound.

The compound \(\mathrm{X}_{2}\left(\mathrm{YZ}_{3}\right)_{3}\) has a molar mass of \(282.23 \mathrm{~g}\) and a percent composition (by mass) of \(19.12 \% \mathrm{X}, 29.86 \% \mathrm{Y}\), and \(51.02 \% \mathrm{Z}\). What is the formula of the compound?

Researchers at Anna Gudmundsdottir's laboratory at the University of Cincinnati have been studying extremely reactive chemicals known as radicals. One of the interesting phenomena they have discovered is that these radicals can be chemically attached to fragrance molecules, effectively tethering them to a solution. When light strikes these tethered molecules, the fragrance is released. This property would allow us to produce perfumes, cleansers, and other consumer products that release fragrance only when exposed to light. If limonene, \(\mathrm{C}_{10} \mathrm{H}_{16}\), the molecule that gives fruits their citrus scent, were able to be tethered to one of these radicals and every photon of light would release one molecule of limonene, calculate the time in seconds required to release \(1.00\) picogram of limonene if ambient light releases \(2.64 \times 10^{18} \mathrm{photons} / \mathrm{sec}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free