\- Copper is often added to paint for oceangoing ships and boats to discourage the growth of marine organisms on their hulls. Unfortunately the copper dissolves into the water and is toxic to the marine life in harbors where these boats are docked. When copper(II) ions reach a concentration of \(9.0\) microgram/L, the growth of some marine life slows. How many copper ions are found in a liter of water containing \(9.0\) micrograms of \(\mathrm{Cu}^{2+} / \mathrm{L}\) ?

Short Answer

Expert verified
Approximately \(8.55 \times 10^{16}\) copper ions.

Step by step solution

01

Understanding the problem

The question requires determining the number of copper ions in 1 liter of water, given a concentration of 9.0 micrograms of \(\text{Cu}^{2+}\) per liter.
02

Convert micrograms to grams

To convert the amount of copper from micrograms to grams, use the conversion factor: \(1 \text{ microgram} = 1 \times 10^{-6} \text{ grams}\). Thus, \(9.0 \text{ micrograms} = 9.0 \times 10^{-6} \text{ grams}\).
03

Find the moles of copper ions

Use the molar mass of copper (63.55 g/mol) to convert grams to moles. \( \text{Moles of } \text{Cu}^{2+} = \frac{9.0 \times 10^{-6} \text{ grams}}{63.55 \text{ g/mol}} \approx 1.42 \times 10^{-7} \text{ moles}\).
04

Determine the number of ions

Using Avogadro's number, which is \(6.022 \times 10^{23} \text{ ions/mole}\), calculate the number of copper ions: \( \text{Number of ions} = 1.42 \times 10^{-7} \text{ moles} \times 6.022 \times 10^{23} \text{ ions/mole} \approx 8.55 \times 10^{16} \text{ ions}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conversion Factors
Conversion factors play a crucial role in stoichiometry, bridging different units of measurement seamlessly. They are used to convert quantities like mass, volume, and particles into terms that are easier to work with. In the given exercise, we needed to convert micrograms to grams to make further calculations manageable.
For instance, knowing that 1 microgram equals 1 \( \times \) 10^{-6} grams helps in changing quantities from micrograms (µg) to more familiar grams (g). This conversion establishes a common ground where other calculations, such as determining moles, become simpler. Here, we used the conversion factor to turn 9.0 µg into 9.0 \( \times \) 10^{-6} grams.
It’s essential to remember that conversion factors are always consistent. Multiplying or dividing by them doesn't alter the actual worth of a quantity; it simply represents it in a different unit. For easier understanding, imagine converting minutes into hours; this is precisely the same concept.
Moles and Grams
Understanding the relationship between moles and grams is foundational in stoichiometry. It's all about converting the mass of a substance to its quantity in moles, which are the 'chemist's dozen'.
To convert grams to moles, you use the molar mass of the substance, which represents how many grams one mole of that substance weighs. In our problem, the molar mass of copper (Cu) is 63.55 g/mol. This indicates that one mole of copper weighs 63.55 grams.
By dividing the mass of the copper ions (9.0 \( \times \) 10^{-6} grams) by the molar mass (63.55 g/mol), we determine the quantity of copper ions in moles. This operation simplifies to:
\[ \text{Moles of}\, \text{Cu}^{2+} = \frac{9.0 \times 10^{-6} \text{ grams}}{63.55 \text{ g/mol}} \approx 1.42 \times 10^{-7} \text{ moles} \].
This calculation transforms a tangible quantity of a substance into a more usable form for further analysis, such as determining the number of particles using Avogadro's number.
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry, representing the number of particles (atoms, molecules, ions) in one mole of a substance. This number is \[ 6.022 \times 10^{23} \], a conveniently large number to relate macroscopic measurements to atomic-scale quantities.
Once moles of a substance are known, Avogadro's number can convert this to the actual count of individual particles. For example, after calculating that we have 1.42 \( \times \) 10^{-7} moles of copper ions (Cu^{2+}), we multiply by Avogadro's number to find the number of ions: \[ \text{Number of}\, \text{ions} = 1.42 \times 10^{-7} \text{ moles} \times 6.022 \times 10^{23} \text{ ions/mole} \approx 8.55 \times 10^{16} \text{ ions} \].
This allows us to transition from a macroscopic amount of material to an exact microscopic count, providing a clear bridge between the bulk properties of materials and their molecular makeup.
Chemical Concentrations
Chemical concentration refers to the amount of a substance within a given volume. It’s a critical concept in chemistry since it affects reactivity, toxicity, and many other properties of a solution.
Concentrations can be expressed in several units like molarity (moles per liter), mass per volume (grams per liter or micrograms per liter), and percentage compositions, among others. In our exercise, concentration is given as micrograms per liter (µg/L), specifically 9.0 µg/L for copper ions (Cu^{2+}).
Understanding concentrations helps us relate macroscopic measurements to the potential impact of those substances. Higher concentrations can mean more pronounced effects—a higher toxic impact in the case of our problem scenario. For calculations, converting the given concentration into a more manageable form (like moles per liter using conversion factors and molar mass) allows for deeper insights and answers at the molecular level.

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Most popular questions from this chapter

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