An American press release describing the 1986 nonstop, round-the-world trip by the ultra-lightweight aircraft Voyager included the following data: flight distance: \(25,012 \mathrm{mi}\) flight time: 9 days, 3 minutes, 44 seconds fuel capacity: nearly 9000 lb fuel remaining at end of flight: \(14 \mathrm{gal}\) To the maximum number of significant figures permitted, calculate (a) the average speed of the aircraft in kilometers per hour (b) the fuel consumption in kilometers per kilogram of fuel (assume a density of \(0.70 \mathrm{g} / \mathrm{mL}\) for the fuel)

To find the average speed of the aircraft, we first need to convert the flight distance from mile to kilometer, and flight time from days to hours. 1 mile is equal to 1.60934 kilometers and 1 day is equal to 24 hours.The formula to calculate speed is given by:Speed = Distance / TimeConverted flight distance = \(25,012 \times 1.60934 = 40,230.77688 \, kilometers\)Converted flight time = \(9 \times 24 + \frac{3}{60} + \frac{44}{3600} = 216.0511 \, hours\)Now, we plug in these values into the formula to get the speed:Speed = \( \frac{40,230.77688}{216.0511} = 186.21 \, km/hr\) (to five significant digits)

To calculate fuel consumption, we need to know the weight of the consumed fuel in kilograms and then divide the total distance traveled by this weight. Before that, we have to convert the fuel weight from pounds to kilograms and volume from gallons to liters. 1 pound is equal to 0.453592 kilograms and 1 gallon is equal to 3.78541 liters.We are given the fuel capacity of 9,000 pounds, and we know that at the end of the flight, 14 gallons of fuel were remaining. We are also given that the fuel density is 0.70 g/mL.First, convert the initial fuel weight from pounds to kilograms: Initial fuel weight = \(9,000 \times 0.453592 = 4,082.328 \, kilograms\)Then, convert the remaining fuel volume from gallons to liters, and then to kilograms:Remaining fuel weight = \(14 \times 3.78541 \times 0.70 = 37.059758 \, kilograms\)Now, find the consumed fuel weight by subtracting remaining fuel weight from the initial fuel weight:Consumed fuel weight = \(4,082.328 - 37.059758 = 4,045.268242 \, kilograms\)Finally, divide the distance traveled by the consumed fuel weight to get the fuel consumption:Fuel consumption = \( \frac{40,230.77688}{4,045.268242} = 9.945 \, kg/km\) (to five significant digits)

In the calculation for average speed and fuel consumption, significant figures were maintained throughout all steps. After computing all values with appropriate conversions of units, final results were rounded off to 5 significant figures. Always ensure conversion of units to international standard units or as required by the problem before doing the calculation.