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Chapter 1: Problem 27

Perform the following conversions. (a) \(0.127 \mathrm{L}=\)_________\(\mathrm{mL}\) (b) \(15.8 \mathrm{mL}=\)_________\(\mathrm{L}\) (c) \(2896 \mathrm{mm}=\)__________\(\mathrm{L}\) (d) \(2.65 \mathrm{m}^{3}=\)__________\(\mathrm{cm}^{3}\)

Short Answer

Expert verified
(a) 127 mL, (b) 0.0158 L, (c) 2.896 L, (d) 2,650,000 cm³

Step by step solution

01

Converting liters to milliliters

1 liter is equivalent to 1000 milliliters. Therefore, to convert liters to milliliters, you multiply the given value by 1000. In this case, \(0.127 L\) is equal to \(0.127 L * 1000 = 127 mL\).
02

Converting milliliters to liters

1 milliliter equals 0.001 liters. Therefore, to convert milliliters to liters, you multiply the given value by 0.001. Therefore, \(15.8 mL\) is equal to \(15.8 mL * 0.001 = 0.0158 L\).
03

Converting millimeters to liters

1 cubic millimeter equals 0.000001 liters. Therefore, to convert cubic millimeters to liters, you multiply the given value by 0.000001. Therefore, \(2896 mm³\) is equal to \(2896 mm³ * 0.000001 = 2.896 L\).
04

Converting meters cubed to centimeters cubed

1 cubic meter (m³) is equivalent to 1,000,000 cubic centimeters (cm³). So to convert from cubic meters to cubic centimeters, the given value is multiplied by 1,000,000. Therefore, \(2.65 m³\) is equal to \(2.65 m³ * 1,000,000 = 2,650,000 cm³\).

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Most popular questions from this chapter

In an engineering reference book, you find that the density of iron is \(0.284 \mathrm{lb} / \mathrm{in.}^{3} .\) What is the density in \(\mathrm{g} / \mathrm{cm}^{3} ?\)

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