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Chapter 1: Problem 31

Which is the greater mass, \(3245 \mu \mathrm{g}\) or \(0.00515 \mathrm{mg} ?\) Explain.

Short Answer

Expert verified
The greater mass is \(3245 \mu g\).

Step by step solution

01

Understanding the Conversion Rates

First, understand the conversion rates. There are \(1,000,000 \mu g \) in a gram and 1000 milligrams in a gram. Therefore, \(1mg = 1000 \mu g\).
02

Convert the Given Values to the Same Unit

Convert the given value of 0.00515 milligrams to micrograms using the conversion rate \(1mg = 1000 \mu g\). So, \(0.00515 mg = 0.00515 \times 1000 \mu g = 5.15 \mu g\)
03

Comparison of Two Masses

Now that both masses are in the same unit, they can easily be compared. The comparison between \(3245 \mu g\) and \(5.15 \mu g \) shows that \(3245 \mu g\) is greater than \(5.15 \mu g \).

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Most popular questions from this chapter

Calculate the mass of a cylinder of stainless steel \(\left(d=7.75 \mathrm{g} / \mathrm{cm}^{3}\right)\) with a height of \(18.35 \mathrm{cm}\) and a radius of \(1.88 \mathrm{cm}\).

The absolute zero of temperature is \(-273.15^{\circ} \mathrm{C}\) Should it be possible to achieve a temperature of \(-465^{\circ} \mathrm{F} ?\) Explain.

List the following in the order of increasing precision, indicating any quantities about which the precision is uncertain: (a) \(1400 \mathrm{km} ;\) (b) \(1516 \mathrm{kg} ;\) (c) \(0.00304 \mathrm{g};\) (d) \(125.34 \mathrm{cm} ;\) (e) \(2000 \mathrm{mg}\).

Which is the greater mass, \(3257 \mathrm{mg}\) or \(0.000475 \mathrm{kg} ?\) Explain.

Express the result of each of the following calculations in exponential form and with the appropriate number of significant figures. (a) \(\left(4.65 \times 10^{4}\right) \times\left(2.95 \times 10^{-2}\right) \times\left(6.663 \times 10^{-3}\right) \times 8.2=\) (b) \(\frac{1912 \times\left(0.0077 \times 10^{4}\right) \times\left(3.12 \times 10^{-3}\right)}{\left(4.18 \times 10^{-4}\right)^{3}}=\) {c} \(\left(3.46 \times 10^{3}\right) \times 0.087 \times 15.26 \times 1.0023=\) (d) \(\frac{\left(4.505 \times 10^{-2}\right)^{2} \times 1.080 \times 1545.9}{0.03203 \times 10^{3}}=\) (e) \(\frac{\left(-3.61 \times 10^{-4}\right)+\sqrt{\left(3.61 \times 10^{-4}\right)^{2}+4(1.00)\left(1.9 \times 10^{-5}\right)}}{2 \times(1.00)}\) [Hint: The significant figure rule for the extraction of a root is the same as for multiplication.]
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