The density of aluminum is \(2.70 \mathrm{g} / \mathrm{cm}^{3} .\) A square piece of aluminum foil, \(22.86 \mathrm{cm}\) on a side is found to weigh 2.568 g. What is the thickness of the foil, in millimeters?

Short Answer

Expert verified
The thickness of the foil is 0.018 mm.

Step by step solution

01

Identify and Write down all Known Variables

Mass of aluminum square = 2.568 g\nDensity of aluminum = 2.70 g/cm³\nSide measurement of aluminum square = 22.86 cm\n
02

Calculate the Volume of the Aluminum Square

The volume can be found using the formula of density: Density = Mass / Volume, rearranged to solve for volume: Volume = Mass / Density.\nSo plugging in the known values for mass and density gives: Volume = 2.568 g / 2.70 g/cm³ = 0.95 cm³.
03

Determine the Thickness of the Foil

Since the foil is a square, the volume of the aluminum square can be expressed as Volume = side² * thickness.\nRearranging to solve for thickness, we get: thickness = Volume / side².\nSubstituting the known values gives: thickness = 0.95 cm³ / (22.86 cm)² = 0.0018 cm.\nFinally, convert the thickness into millimeters (since 1 cm = 10 mm): thickness = 0.0018 cm * 10 = 0.018 mm.

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