Write a plausible Lewis structure for \(\mathrm{C}_{3} \mathrm{O}_{2},\) a substance known as carbon suboxide.

Short Answer

Expert verified
The correct Lewis structure for \(C_{3}O_{2}\) or carbon suboxide has the skeletal structure O-C-C-C-O, with two single bonds linking the Oxygen and the Carbon atoms, and double bonds linking the Carbon atoms. 8 electrons are distributed around the Oxygen atoms, satisfying the 'octet rule'.

Step by step solution

01

Calculation of Total Valence Electrons

Calculate the total number of valence electrons. This is computed by adding the number of valence electrons from each atom. Since C (Carbon) has 4 valence electrons and there are 3 carbon atoms, the total valence electrons from carbon is \(4*3 = 12\). On the other hand, O (Oxygen) has 6 valence electrons and there are 2 oxygen atoms. The total valence electrons from oxygen is \(6*2 = 12\). Therefore, total valence electrons in the \(C_{3}O_{2}\) molecule is \(12 + 12 = 24\).
02

Construct the Skeletal Structure

Determine the skeletal structure of the molecule. In \(C_{3}O_{2}\), the carbon (C) atoms are usually in the center because oxygen (O) is more electronegative. Hence, the skeletal structure will look like O-C-C-C-O.
03

Distribute the Remaining Electrons

Start by placing two electrons (as a bond) between each pair of bonded atoms. Then add lone pairs of electrons around each atom until each atom (except Hydrogen) is surrounded by 8 electrons or until you have used all the electrons. Remember, each bond represents two electrons. After placing the first 8 electrons (4 bonds of 2 electrons each), 16 electrons are left. Place these around the oxygen atoms (8 electrons around each oxygen). Now, each atom is surrounded by 8 electrons, satisfying the octet rule.
04

Verify and Confirm Structure

Double-check the structure to confirm that the octet rule is obeyed for every atom (except Hydrogen) and that all the valence electrons have been used. If the octet rule has been violated, adjust the structure by converting lone pairs to bonding pairs for atoms violating the rule. For \(C_{3}O_{2}\), no such adjustments are necessary because the octet rule is obeyed for every atom and all 24 valence electrons are used. Hence, the Lewis structure is correct as it is.

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