Use VSEPR theory to predict the geometric shapes of the following molecules and ions: (a) \(\mathrm{N}_{2}\); (b) HCN; (c) \(\mathrm{NH}_{4}^{+} ;\) (d) \(\mathrm{NO}_{3}^{-} ;\) (e) NSF.

Short Answer

Expert verified
The shapes of the molecules and ions are as follows: (a) \(\mathrm{N}_{2}\) - Linear; (b) HCN - Linear; (c) \(\mathrm{NH}_{4}^{+} ;\) - Tetrahedral; (d)\(\mathrm{NO}_{3}^{-} ;\) - Trigonal Planar; (e) NSF - Bent or V-Shaped.

Step by step solution

01

Calculate Steric Number for N2

As nitrogen (N) has five valence electrons, N2 means that each nitrogen shares three electrons with each other. Thus, the steric number becomes 3 and the shape is Linear.
02

Predict Shape for HCN

Carbon (C), the central atom here, has 4 valence electrons. In HCN, it forms a double bond with Nitrogen (N) and a single bond with Hydrogen (H). Total bonded electrons = 4, so the steric number is 4 (3 from N and 1 from H). Hence, the shape is Linear.
03

Predict Shape for NH4+

Nitrogen (N) has 5 valence electrons. In Ammonium ion (NH4+), it forms 4 bonds with Hydrogens so total bonded electrons = 8 (4x2 from each H). The steric number is 4, which leads to a Tetrahedral shape.
04

Predict Shape for NO3-

In Nitrate ion (NO3-), Nitrogen (N) is the central atom with 5 valence electrons. It forms three bonds (2 with one Oxygen and 1 with two others). In total, bonded electrons = 6 (2x3 from each O). The steric number is 3, hence the shape is Trigonal Planar.
05

Predict Shape for NSF

In NSF, Sulphur (S) is the central atom with 6 valence electrons. It forms 2 single bonds with Nitrogen and Fluorine, so total bonded electrons = 4 (2x2 from each N, F). The steric number is 4, therefore the shape is Bent or V-Shaped.

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