Use the VSEPR theory to predict the shape of (a) the molecule OSF \(_{2} ;\) (b) the molecule \(\mathrm{O}_{2} \mathrm{SF}_{2} ;\) (c) the ion \(\mathrm{SF}_{5}^{-} ;\) (d) the ion \(\mathrm{ClO}_{4}^{-} ;\) (e) the ion \(\mathrm{ClO}_{3}^{-}\).

Short Answer

Expert verified
The molecule OSF2 has a T-shaped, O2SF2 and ClO4- are tetrahedral, SF5- is square pyramidal, and ClO3- is a Trigonal Pyramid.

Step by step solution

01

Identify the central atom

For OSF2, O2SF2, SF5-, and ClO4-, the central atom is S. For ClO3-, it's Cl.
02

Drawing the Lewis structures

Draw structures showcasing all involved bonds and lone electron pairs. This helps to visualize the layout of the molecules/ions. You get for OSF2: S is bounded to O and two F with two lone pairs on S. O2SF2 has S bounded to two O and two F, with no lone pairs. SF5- has S surrounded by five one-bonded F atoms with one lone pair. ClO4- has Cl surrounded by four one-bonded O atoms with no lone pairs. ClO3- has one double-bonded O and two one-bonded O surrounding Cl with one lone pair.
03

Applying the AXE notation

This notation helps to predict the geometry of a molecule. The 'A' stands for the central atom, 'X' represents the number of atoms attached to A and 'E' is the number of lone electron pairs. For OSF2, A=S, X=3, E=2 (AX3E2). For O2SF2, A=S, X=4, E=0 (AX4E0). For SF5-, A=S, X=5, E=1 (AX5E1). For ClO4-, A=Cl, X=4, E=0 (AX4E0). For ClO3-, A=Cl, X=3, E=1 (AX3E1).
04

Predicting the shape

Now you can use the AXE notation to predict the shape of the molecules and ions. For OSF2 (AX3E2), it is a T-Shaped. For O2SF2 (AX4E0), it's Tetrahedral. For SF5- (AX5E1), it's a square pyramidal. For ClO4- (AX4E0), it's also Tetrahedral. For ClO3- (AX3E1), it's a Trigonal Pyramid.

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