What is the total number of (a) \(\sigma\) bonds and (b) \(\pi\) bonds in the molecule \(\mathrm{CH}_{3} \mathrm{NCO}\) ?

Short Answer

Expert verified
The molecule \(\mathrm{CH}_{3} \mathrm{NCO}\) has a total of 6 sigma bonds and 2 pi bonds.

Step by step solution

01

Break down molecule into structural formula

Firstly, it is necessary to know the molecular structure of \(\mathrm{CH}_{3} \mathrm{NCO}\). The structure is H3C-N=C=O, where the hyrdocarbon \(CH_{3}\) is bonded with Nitrogen, Nitrogen is double bonded with Carbon and Carbon is double bonded with Oxygen.
02

Count sigma bonds

Each single bond and each part of a double or triple bond is a sigma bond. So, in the molecule structure, there are three sigma bonds in the \(\mathrm{CH}_{3}\) group (between Carbon and Hydrogen atoms) and three more within the rest of the molecule (between Carbon-Nitrogen and Carbon-Oxygen). So, in total there are 6 sigma bonds.
03

Count pi bonds

Pi bonds are the 'extra' bonds in a double bond (N=C, C=O). For each double bond, there is one pi bond. Therefore, there are two pi bonds in the \(\mathrm{CH}_{3} \mathrm{NCO}\) molecule.

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