For each of the species \(\mathrm{C}_{2}^{+}, \mathrm{O}_{2}^{-}, \mathrm{F}_{2}^{+},\) and \(\mathrm{NO}^{+}\) (a) Write the molecular orbital diagram (as in Example \(11-6)\) (b) Determine the bond order, and state whether you expect the species to be stable or unstable. (c) Determine if the species is diamagnetic or paramagnetic; and if paramagnetic, indicate the number of unpaired electrons.

Short Answer

Expert verified
For \(\mathrm{C}_{2}^{+}\), the bond order is 3, it is expected to be stable, and it is diamagnetic. For \(\mathrm{O}_{2}^{-}\), follow the steps to find these same characteristics. Repeat for \(\mathrm{F}_{2}^{+}\) and \(\mathrm{NO}^{+}\).

Step by step solution

01

Writing the molecular orbital diagram

Using the molecular orbital theory, diagram the arrangement of electrons for each species. This involves placing the appropriate number of electrons into the increasingly energetic molecular orbital levels. For \(\mathrm{C}_{2}^{+}\), the configuration is \(\sigma_{1s}^{2}\sigma_{1s*}^{2}\sigma_{2s}^{2}\sigma_{2s*}^{2}\pi_{2p}^{2}\) - one electron less than the \(\mathrm{C}_2\) diagram due to the positive charge. Repeat this for \(\mathrm{O}_{2}^{-}\), \(\mathrm{F}_{2}^{+}\), and \(\mathrm{NO}^{+}\).
02

Determining the bond order and stability

The bond order is calculated by the formula \(\frac{1}{2}(nb-na)\), where \(nb\) is the number of electrons in bonding orbitals and \(na\) is the number in antibonding orbitals. For example for \(\mathrm{C}_{2}^{+}\), the bond order would be \(\frac{1}{2}(8-2) = 3\). A positive bond order generally implies a stable molecule, while a negative or zero bond order implies instability. Repeat this for \(\mathrm{O}_{2}^{-}\), \(\mathrm{F}_{2}^{+}\), and \(\mathrm{NO}^{+}\).
03

Determine magnetic properties

A species is diamagnetic if all of its electrons are paired, and paramagnetic if it has one or more unpaired electrons. Regarding the \(\mathrm{C}_{2}^{+}\), there are no unpaired electrons, making it diamagnetic. Repeat the process for \(\mathrm{O}_{2}^{-}\), \(\mathrm{F}_{2}^{+}\), and \(\mathrm{NO}^{+}\). If a species is found to be paramagnetic, indicate the number of unpaired electrons by simply counting them in the orbital diagram.

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Most popular questions from this chapter

Construct the molecular orbital diagram for CF. Would you expect the bond length of \(\mathrm{CF}^{+}\) to be longer or shorter than that of CF?

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