Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 11: Problem 49

From this list of terms-electrical conductor, insulator, semiconductor- -choose the one that best characterizes each of the following materials: (a) stainless steel; (b) solid sodium chloride; (c) sulfur; (d) germanium; (e) seawater; (f) solid iodine.

Short Answer

Expert verified
(a) Stainless steel is an electrical conductor. (b) Solid sodium chloride is an insulator. (c) Sulfur is an insulator. (d) Germanium is a semiconductor. (e) Seawater is an electrical conductor. (f) Solid iodine is an insulator.

Step by step solution

01

Categorize stainless steel

Stainless steel is a metal and metals are good conductors of electricity. Therefore, stainless steel is an electrical conductor.
02

Categorize solid sodium chloride

Solid sodium chloride does not conduct electricity well, however, when dissolved in water (or melted), it becomes a strong electrical conductor due to ionization. Therefore, in its solid state, sodium chloride is an insulator.
03

Categorize sulfur

Sulfur is a non-metal and it does not conduct electricity well. Therefore, sulfur is an insulator.
04

Categorize germanium

Germanium is a semiconductor material. It is neither a good electrical conductor nor a good insulator.
05

Categorize seawater

Seawater contains salts which ionize and therefore, it conducts electricity well. So, seawater is an electrical conductor.
06

Categorize solid iodine

Solid iodine is a non-metal and it doesn't conduct electricity well. Therefore, iodine is an insulator.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In what type of material is the energy gap between the valence band and the conduction band greatest: metal, semiconductor, or insulator? Explain.

The compound potassium sesquoxide has the empirical formula $\mathrm{K}_{2} \mathrm{O}_{3}$. Show that this compound can be described by an appropriate combination of potassium, peroxide, and superoxide ions. Write a Lewis structure for a formula unit of the compound.

The best electrical conductor of the following materials is (a) \(\mathrm{Li}(\mathrm{s}) ;\) (b) \(\mathrm{Br}_{2}(\mathrm{l}) ;\) (c) \(\mathrm{Ge}(\mathrm{s}) ;\) (d) \(\mathrm{Si}(\mathrm{s})\).

Methyl nitrate, \(\mathrm{CH}_{3} \mathrm{NO}_{3}\), is used as a rocket propellant. The skeletal structure of the molecule is \(\mathrm{CH}_{3} \mathrm{ONO}_{2}\). The N and three O atoms all lie in the same plane, but the \(\mathrm{CH}_{3}\) group is not in the same plane as the \(\mathrm{NO}_{3}\) group. The bond angle \(\mathrm{C}-\mathrm{O}-\mathrm{N}\) is \(105^{\circ},\) and the bond angle \(\mathrm{O}-\mathrm{N}-\mathrm{O}\) is \(125^{\circ} .\) One nitrogen-to-oxygen bond length is \(136 \mathrm{pm},\) and the other two are \(126 \mathrm{pm}\) (a) Draw a sketch of the molecule showing its geometric shape. (b) Label all the bonds in the molecule as \(\sigma\) or \(\pi\), and indicate the probable orbital overlaps involved. (c) Explain why all three nitrogen-to-oxygen bond lengths are not the same.

Why does the hybridization \(s p^{3} d\) not account for bonding in the molecule BrF \(_{5} ?\) What hybridization scheme does work? Explain.
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Kinetics

Read Explanation

Chemical Reactions

Read Explanation

Organic Chemistry

Read Explanation

Making Measurements

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free