The bond angle in \(\mathrm{H}_{2} \mathrm{Se}\) is best described as (a) between \(109^{\circ}\) and \(120^{\circ} ;\) (b) less than in \(\mathrm{H}_{2} \mathrm{S} ;\) (c) less than in \(\mathrm{H}_{2} \mathrm{S},\) but not less than \(90^{\circ} ;(\mathrm{d})\) less than \(90^{\circ}\)

Short Answer

Expert verified
The bond angle in \(\mathrm{H}_{2} \mathrm{Se}\) is between \(109^{\circ}\) and \(120^{\circ}\), hence option (a) in the original problem is the most accurate

Step by step solution

01

Understand the Electron Pair Repulsion Theory

Valence Shell Electron Pair Repulsion (VSEPR) Theory is a simple, qualitative model that allows us to predict the geometry of polyatomic ions, molecules, and atoms based on the repulsion between electrons in the outer shell of atoms. It assumes that the molecule or ion will adopt a shape that minimizes the repulsion between electrons in the valence shell of that atom.
02

Identify the Molecular Structure of $\mathrm{H}_{2} \mathrm{Se}$ and $\mathrm{H}_{2}\mathrm{S}$

Both \(\mathrm{H}_{2} \mathrm{Se}\) and \(\mathrm{H}_{2}\mathrm{S}\) are nonpolar and fall under the AX2E (where A is the central atom, X is a terminal atom, and E stands for a lone pair of electrons on the central atom) category based on VSEPR theory. In these structures, the central atom (Se or S) is bonded to two hydrogen atoms and has two lone pairs of electrons.
03

Determine the Theoretical Bond Angle for AX2E Structures

In an AX2E structure, the ideal bond angle would be \(109.5^{\circ}\), but due to the presence of the lone pair electrons on the central atom, there is more repulsion between the lone pair and the bonding pairs. This causes the bonding pairs to squeeze together. As such, the bond angle is slightly less than \(109.5^{\circ}\). Therefore the bond angle in \(\mathrm{H}_{2} \mathrm{Se}\) and \(\mathrm{H}_{2}\mathrm{S}\) will be less than \(109.5^{\circ}\).
04

Compare the Bond Angles of $\mathrm{H}_{2} \mathrm{Se}$ and $\mathrm{H}_{2}\mathrm{S}$

H2Se has larger central atom (Se) than H2S (S), thus the size of S is smaller than that of Se which means Se has inner shells that shield the lone pairs more than the smaller S atom. Therefore the lone pair in Se is more diffuse. This makes the bond angle in H2Se larger than in H2S

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