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Chapter 12: Problem 102

A cylinder containing 151 lb \(\mathrm{Cl}_{2}\) has an inside diameter of 10 in. and a height of 45 in. The gas pressure is 100 psi \((1 \mathrm{atm}=14.7 \mathrm{psi})\) at \(20^{\circ} \mathrm{C} . \mathrm{Cl}_{2}\) melts at \(-103^{\circ} \mathrm{C},\) boils at \(-35^{\circ} \mathrm{C},\) and has its critical point at \(144^{\circ} \mathrm{C}\) and \(76 \mathrm{atm} .\) In what state \((\mathrm{s})\) of matter does the \(\mathrm{Cl}_{2}\) exist in the cylinder?

Short Answer

Expert verified
The state of the Chlorine (Cl2) in the cylinder is gas.

Step by step solution

01

Convert pressure units

The pressure is given in psi, and we need to convert it to atm. Using the conversion rate given (1 atm = 14.7 psi), we can find the pressure in atm. We do this by dividing the given pressure by the conversion rate: \(100 \, \text{psi} \, / \, 14.7 \, \text{psi/atm} = 6.8 \, \text{atm}\)
02

Compare condition with critical point

Compare the obtained pressure and given temperature with the critical point data. The critical point is given as 144°C and 76 atm. The condition inside the cylinder which is 6.8 atm and 20°C is well below these values.
03

Determine the state of Cl2

Considering that the pressure and temperature in the tank are below the critical point values, refer to the boiling and melting points of Cl2. The boiling point is -35°C and the melting point is -103°C. Given the temperature inside the tank is 20°C, which is higher than the boiling point, the chlorine in the tank will be in a gaseous state.

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Most popular questions from this chapter

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