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Chapter 12: Problem 143

In the lithium iodide crystal, the Li-I distance is \(3.02 \AA\) Calculate the iodide radius, assuming that the iodide ions are in contact.

Short Answer

Expert verified
The iodide radius in a Lithium Iodide crystal is 226 pm.

Step by step solution

01

Conversion of Li-I distance to a common unit

First, convert the Li-I distance from \(\AA\) to picometers (pm), because the radius of an atom is typically expressed in pm. To do this, recall that \(1 \AA = 100 \, pm\). Hence, the Li-I distance is \(3.02 \, \AA \times 100 = 302 \, pm\).
02

Calculation of Iodide Radius

Next, subtract the radius of the Lithium ion from the Li-I distance to find the Iodide radius. The generally accepted radius of a Lithium ion is 76 pm. Therefore, the Iodide radius would be \(302 \, pm - 76 \, pm = 226 \, pm\). This means the radius of the Iodide ion in a lithium iodide crystal is 226 pm.

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Most popular questions from this chapter

Estimate the boiling point of water in Leadville, Colorado, elevation 3170 m. To do this, use the barometric formula relating pressure and altitude: \(P=P_{0} \times 10^{-\mathrm{Mgh} / 2.303 \mathrm{RT}} \quad(\text { where } P=\text { pressure } \mathrm{in}\) atm; \(P_{0}=1 \mathrm{atm} ; g=\) acceleration due to gravity; molar mass of air, \(M=0.02896 \mathrm{kg} \mathrm{mol}^{-1} ; \quad R=\) \(8.3145 \mathrm{Jmol}^{-1} \mathrm{K}^{-1} ;\) and \(T\) is the Kelvin temperature). Assume the air temperature is \(10.0^{\circ} \mathrm{C}\) and that \(\Delta H_{\text {vap }}=41 \mathrm{kJ} \mathrm{mol}^{-1} \mathrm{H}_{2} \mathrm{O}\)

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Construct a concept map showing the ideas contained in a phase diagram.

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