Trace the phase changes that occur as a sample of \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g}),\) originally at \(1.00 \mathrm{mmHg}\) and \(-0.10^{\circ} \mathrm{C},\) is compressed at constant temperature until the pressure reaches 100 atm.

Short Answer

Expert verified
The $H_{2}O_{(g)}$ sample goes through phase changes from gas to liquid and then to solid as the pressure increases from 1.00 mmHg to 100 atm at a constant temperature of -0.10°C.

Step by step solution

01

Identify initial state

The sample of water begins as gas (\(H_{2}O_{(g)}\)) and is under low pressure (1.00 mmHg) and low temperature (-0.10°C). Utilize the phase diagram of water to initially place the state.
02

Follow the isotherm

Start from the initial position identified in Step 1, and trace horizontally along the isotherm (constant temperature) line as the pressure increases. The phase will change from gas to liquid as the pressure reaches the vapor pressure line for -0.10°C.
03

Reach final state

Keep tracing along the isotherm line until pressure reaches 100 atm. As the pressure keeps increasing, the phase will then change from liquid to solid - contrary to most substances but characteristic for water due to its density anomalies.

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