What is the weight percent of \(23.4 \mathrm{g}\) of \(\mathrm{CaF}_{2}\) if dissolved in 10.5 mol of water? (a) \(0.028\); (b)\( 1.59\);(c) \(11.0\); (d) \(12.4 ;\) (e) none of these.

Short Answer

Expert verified
The weight percent of \(23.4 g\) of \(CaF_{2}\) if dissolved in 10.5 mol of water is approximately 11.01%. So, the closest answer choice is (c) 11.0. If none of the options were close enough, then (e) 'none of these' would be chosen.

Step by step solution

01

Identify Given Information

Extract the given values from the problem - the mass of the solute (Calcium Fluoride - \(CaF_{2}\)) which is \(23.4 g\), and volume of the solvent (Water - \(H_{2}O\)) expressed in moles, which is 10.5mol.
02

Convert Moles of Solvent to Mass

Convert the moles of water to grams using water’s molar mass (18.02 g/mol). So, the mass of the water = 10.5 mol * 18.02 g/mol = 189.21 g.
03

Calculate the total mass of the solution

Add the mass of the solute (\(CaF_{2}\)) to the mass of the solvent (water) to find the total mass of the solution. The total mass = 23.4g (\(CaF_{2}\)) + 189.21g (water) = 212.61 g.
04

Calculate Weight Percentage

Use the weight percentage formula: (Mass of solute / Total mass of solution) * 100. So, weight percent = (23.4 g / 212.61 g) * 100 = 11.01%.

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