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Chapter 13: Problem 18

A water sample is found to have 9.4 ppb of chloroform, \(\mathrm{CHCl}_{3} .\) How many grams of \(\mathrm{CHCl}_{3}\) would be found in a glassful \((250 \mathrm{mL})\) of this water?

Short Answer

Expert verified
There would be \(2.35 \times 10^{-6}\) grams of chloroform in a glassful (250 mL) of this water.

Step by step solution

01

Convert volume from mL to Liters

Given that \(1 \text{ L} = 1000 \text{ mL}\), we can convert the volume from mL to L by dividing by \(1000\). Hence, \(250 \text{ mL} = 250 / 1000 = 0.25 \text{ L}\).
02

Calculate the mass of chloroform in the volume of the water

Using the equation \(Mass = \text{volume} × \text{concentration}\), substitute the values. Concentration of 1ppb chloroform in water implies there is \(1 \text{ gram}\) of chloroform in \(10^9 \text{ g}\) (or \(\10^9 \text{ mL}\)) of water. Hence, the mass of chloroform in \(0.25 \text{ L}\) of water is \(0.25 × 9.4 = 2.35 \times 10^{-6} \text{ g}\).

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