The following very strong acids are formed by the reactions indicated: $$ \mathrm{HF}+\mathrm{SbF}_{5} \longrightarrow \mathrm{HSb} \mathrm{F}_{6} $$ (called "super acid," hexafluoroantimonic acid) $$ \mathrm{HF}+\mathrm{BF}_{3} \longrightarrow \mathrm{HBF}_{4} $$ (tetrafluoroboric acid) (a) Identify the Lewis acids and bases. (b) To which atom is the H atom bonded in each acid?

Short Answer

Expert verified
(a) Lewis Acids: \( \mathrm{SbF}_{5} \), \( \mathrm{BF}_{3} \); Lewis Bases: \( \mathrm{HF} \) (b) In \( \mathrm{HSbF}_{6} \), H is bonded to Sb; in \( \mathrm{HBF}_{4} \), H is bonded to B.

Step by step solution

01

Identify Lewis Acids And Bases

In the given reactions, \( \mathrm{HF} \) is the Lewis base in both reactions as it donates an electron pair. In the first reaction, \( \mathrm{SbF}_{5} \) is the Lewis acid as it accepts an electron pair. In the second reaction, \( \mathrm{BF}_{3} \) is the Lewis acid as it also accepts an electron pair.
02

Identify Atoms Bonded to Hydrogen

To find which atom is bonded to the H atom in each acid, analyze the molecular structure of the products from the initial reactions. In \( \mathrm{HSbF}_{6} \), the H atom is bonded to Sb atom. Similarly, in \( \mathrm{HBF}_{4} \), the H atom is bonded to the B atom.

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