Explain the important distinctions between each pair of terms: (a) buffer capacity and buffer range; (b) hydrolysis and neutralization; (c) first and second equivalence points in the titration of a weak diprotic acid; (d) equivalence point of a titration and end point of an indicator.

Short Answer

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Buffer capacity is the amount of an acid or base the buffer can absorb without a significant pH change while buffer range is the pH range where the buffer effectively resists changes in pH. Hydrolysis involves a compound reacting with water, often forming either acidic or basic solutions, while neutralization is a reaction between an acid and a base to form a salt and water. In a weak diprotic acid titration, the first equivalence point is where all the first protons have been neutralized, and the second equivalence point is when all the second protons have been neutralized. The equivalence point in titration is when the reaction is theoretically complete, while the end point is the point where the indicator changes color.

Step by step solution

01

Understanding Buffer Capacity and Buffer Range

Buffer capacity refers to the amount of an acid or base that can be added to a buffer solution before its pH starts to change significantly. It reflects the quality of a buffer solution in resisting changes in pH. On the other hand, buffer range is related to the pH range within the buffer effectively maintains a constant pH level. Typically, a buffer is most effective when the pH is within 1 pH unit from the pKa of the buffering system.
02

Distinguishing Hydrolysis from Neutralization

Hydrolysis is a reaction in which a compound interacts with water to form a new compound. In the context of acid-base chemistry, hydrolysis usually refers to how salts react with water to produce either an acidic or basic solution. In contrast, neutralization refers to the reaction between an acid and a base, producing a salt and water. The resulting solution is generally neutral (pH=7), hence the term 'neutralization'.
03

Defining First and Second Equivalence Points

In the context of the titration of a weak diprotic acid (an acid that can donate two protons per molecule), the first equivalence point refers to the stage in titration where one equivalent of base has reacted with one equivalent of acid. At the first equivalence point, all the first protons from the acid have been neutralized. The second equivalence point, on the other hand, is reached when a second equivalent of base has been added, neutralizing all the second protons from each acid molecule.
04

Explaining Equivalence Point and End Point

The equivalence point of a titration is the point at which an equivalent amount of the titrant has been added to the solution being titrated, meaning the reaction is theoretically complete. In contrast, the end point of an indicator refers to the point in a titration at which the indicator changes color. The ideal scenario would be for the end point of the indicator to coincide with the equivalence point of the titration, although in practice there may be slight differences, leading to small errors in the titration results.

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Most popular questions from this chapter

The most acidic of the following \(0.10 \mathrm{M}\) salt solutions is (a) \(\mathrm{Na}_{2} \mathrm{S} ;\) (b) \(\mathrm{NaHSO}_{4} ;\) (c) \(\mathrm{NaHCO}_{3} ;\) (d) \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\)

Given \(125 \mathrm{mL}\) of a solution that is \(0.0500 \mathrm{M} \mathrm{CH}_{3} \mathrm{NH}_{2}\) and \(0.0500 \mathrm{M} \mathrm{CH}_{3} \mathrm{NH}_{3}^{+} \mathrm{Cl}^{-}\) (a) Over what pH range will this solution be an effective buffer? (b) What is the buffer capacity of the solution? That is, how many millimoles of strong acid or strong base can be added to the solution before any significant change in pH occurs?

You are asked to prepare a \(\mathrm{KH}_{2} \mathrm{PO}_{4}-\mathrm{Na}_{2} \mathrm{HPO}_{4}\) solu- tion that has the same \(\mathrm{pH}\) as human blood, 7.40 (a) What should be the ratio of concentrations \(\left[\mathrm{HPO}_{4}^{2-}\right] /\left[\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\right]\) in this solution? (b) Suppose you have to prepare \(1.00 \mathrm{L}\) of the solution described in part (a) and that this solution must be isotonic with blood (have the same osmotic pressure as blood). What masses of \(\mathrm{KH}_{2} \mathrm{PO}_{4}\) and of \(\mathrm{Na}_{2} \mathrm{HPO}_{4} \cdot 12 \mathrm{H}_{2} \mathrm{O}\) would you use? [Hint: Refer to the definition of isotonic on page \(580 .\) Recall that a solution of \(\mathrm{NaCl}\) with \(9.2 \mathrm{g} \mathrm{NaCl} / \mathrm{L}\) solution is isotonic with blood, and assume that \(\mathrm{NaCl}\) is completely ionized in aqueous solution.]

Is a solution that is \(0.10 \mathrm{M} \mathrm{Na}_{2} \mathrm{S}(\mathrm{aq})\) likely to be acidic, basic, or pH neutral? Explain.

A \(25.00 \mathrm{mL}\) sample of \(\mathrm{H}_{3} \mathrm{PO}_{4}(\text { aq) requires } 31.15 \mathrm{mL}\) of \(0.2420 \mathrm{M}\) KOH for titration to the second equivalence point. What is the molarity of the \(\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{aq}) ?\)

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