Indicate whether each of the following changes represents an increase or a decrease in entropy in a system, and explain your reasoning: (a) the freezing of ethanol; (b) the sublimation of dry ice; (c) the burning of a rocket fuel.

Short Answer

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(a) The freezing of ethanol decreases entropy. (b) The sublimation of dry ice increases entropy. (c) The burning of rocket fuel increases entropy.

Step by step solution

01

Freezing of Ethanol

During the freezing process, particles move from a less ordered state (liquid) to a more ordered state (solid). The particles in the solid state are closely packed and have less movement compared to the liquid state. Therefore, freezing decreases the system's entropy.
02

Sublimation of Dry Ice

Sublimation is the process by which a substance transitions from the solid state directly to the gaseous state, bypassing the liquid state. In the case of dry ice (solid carbon dioxide), the particles in the gas state are much more disordered and spread out than in the solid state. Therefore, the sublimation of dry ice increases the system's entropy.
03

Burning of Rocket Fuel

The burning of rocket fuel is a chemical reaction that converts reactants (ordered molecules) into products in the form of various gases. These gases spread out and increase the disorder of the system. Therefore, the burning of rocket fuel increases the system's entropy.

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Most popular questions from this chapter

Use thermodynamic data at \(298 \mathrm{K}\) to decide in which direction the reaction $$2 \mathrm{SO}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{SO}_{3}(\mathrm{g})$$ is spontaneous when the partial pressures of \(\mathrm{SO}_{2}, \mathrm{O}_{2},\) and \(\mathrm{SO}_{3}\) are \(1.0 \times 10^{-4}, 0.20,\) and \(0.10 \mathrm{atm}\) respectively.

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