The Gibbs energy change of a reaction can be used to assess (a) how much heat is absorbed from the surroundings; (b) how much work the system does on the surroundings; (c) the net direction in which the reaction occurs to reach equilibrium; (d) the proportion of the heat evolved in an exothermic reaction that can be converted to various forms of work.

Short Answer

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a) The Gibbs energy change doesn't directly measure the heat absorbed from the surroundings, that's measured by the enthalpy change. b) Gibbs free energy change reflects the work a system can do on its surroundings excluding expansionary work. c) The direction of the reaction towards equilibrium is determined by whether Gibbs energy change is negative (forward reaction) or positive (reverse reaction). d) Gibbs energy change doesn't specifically indicate the proportion of evolved heat that can be converted to work in an exothermic reaction, but it can be inferred from the signs of \( \Delta H \) and \( \Delta S \).

Step by step solution

01

Understanding Gibbs Energy

The Gibbs energy change (\( \Delta G \)) is defined as \( \Delta G = \Delta H - T\Delta S \) where \( \Delta H \) is the change in enthalpy (total energy), \( T \) is the absolute temperature and \( \Delta S \) is change in entropy (disorder). Thus, the change in Gibbs Free Energy accounts for both the energy taken in or given out during a reaction (\( \Delta H \)), and the energy absorbed or released due to changes in disorder (\( T\Delta S \)).
02

Answer to (a)

(a) Gibbs energy change doesn't directly measure the amount of heat absorbed from the surroundings but it relies on the enthalpy change (\( \Delta H \)) which is a measure of the total energy change, part of which relates to heat absorbed or released.
03

Answer to (b)

(b) Gibbs energy change directly shows how much reversible work a system can do on its surroundings, excluding expansion work. If \( \Delta G \) is negative, the system can do work to the surroundings. If \( \Delta G \) is positive, work is done on the system by the surroundings.
04

Answer to (c)

(c) The direction in which the reaction occurs to reach equilibrium is directly related to the Gibbs energy change. If \( \Delta G \) is negative, the reaction will proceed forward spontaneously. If \( \Delta G \) is positive, the reaction will proceed in the reverse direction spontaneously.
05

Answer to (d)

(d) The Gibbs energy change doesn't specifically let us know the proportion of the heat evolved that can be converted to various forms of work. However, in an exothermic reaction (\( \Delta H < 0 \)), if there is also an increase in disorder (\( \Delta S > 0 \)), then a portion of the heat released can be used by the system to do work.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy Change
Enthalpy change, represented by the symbol \( \Delta H \), is a measure of the total heat content change in a chemical reaction. It tells us how much energy, in the form of heat, is either absorbed from or released into the surroundings during the reaction. An exothermic reaction, where \( \Delta H < 0 \), releases heat to the surroundings, making it feel warm to the touch. On the contrary, an endothermic reaction absorbs heat, signified by \( \Delta H > 0 \), making the surroundings feel cooler.

Understanding enthalpy change is crucial because it helps predict whether a reaction will be product-favored under constant pressure. Furthermore, knowing \( \Delta H \) allows us to calculate the energy change in a reaction, which is important from the perspective of energy resources and requirements in chemical processes.
Entropy Change
Entropy change, denoted as \( \Delta S \), is a measure of the disorder or randomness within a system. The second law of thermodynamics states that the total entropy of an isolated system always increases over time. This means that systems naturally progress from a state of order to a state of disorder.

When \( \Delta S > 0 \) there's an increase in entropy, indicating a more disordered system after the reaction. Conversely, \( \Delta S < 0 \) implies a decrease in entropy, representing a more ordered system. Entropy change plays a pivotal role in determining reaction spontaneity through the Gibbs energy equation, as a positive entropy change can drive a reaction to be spontaneous even if it's endothermic.
Reaction Spontaneity
The spontaneity of a chemical reaction refers to whether a reaction can proceed without any external input of energy. Spontaneity is governed by the Gibbs free energy change \( \Delta G \), which incorporates both enthalpy and entropy changes according to the relationship \( \Delta G = \Delta H - T\Delta S \).

A negative \( \Delta G \) indicates a spontaneous reaction, as the process can happen on its own under certain conditions. Positive \( \Delta G \) means the reaction is non-spontaneous and requires external energy to proceed. It's essential to note that spontaneity doesn't imply the rate at which a reaction will occur—some spontaneous reactions can be incredibly slow.
Exothermic Reaction
An exothermic reaction is one where energy, primarily in the form of heat, is released to the surroundings. It is characterized by a negative enthalpy change \( \Delta H < 0 \). These reactions often feel hot as they transfer thermal energy to the environment. Exothermic reactions are common in everyday life, including combustion processes like burning wood or fossil fuels, and metabolic reactions in our bodies.

Moreover, exothermic reactions can be spontaneous when also accompanied by an increase in entropy \( \Delta S > 0 \), leading to \( \Delta G \) being negative. However, the ability to do work, such as electrical or mechanical work, depends on both the heat released and the change in entropy during the reaction.

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Most popular questions from this chapter

If \(\Delta G^{\circ}=0\) for a reaction, it must also be true that (a) \(K=0 ;\) (b) \(K=1 ;\) (c) \(\Delta H^{\circ}=0 ;\) (d) \(\Delta S^{\circ}=0\) (e) the equilibrium activities of the reactants and products do not depend on the initial conditions.

Briefly describe each of the following ideas, methods, or phenomena: (a) absolute molar entropy; (b) coupled reactions; (c) Trouton's rule; (d) evaluation of an equilibrium constant from tabulated thermodynamic data.

At \(298 \mathrm{K},\) for the reaction \(2 \mathrm{H}^{+}(\mathrm{aq})+2 \mathrm{Br}^{-}(\mathrm{aq})+\) \(2 \mathrm{NO}_{2}(\mathrm{g}) \longrightarrow \mathrm{Br}_{2}(1)+2 \mathrm{HNO}_{2}(\mathrm{aq}), \Delta H^{\circ}=-61.6 \mathrm{kJ}\) and the standard molar entropies are \(\mathrm{H}^{+}(\mathrm{aq}), 0 \mathrm{JK}^{-1}\) \(\mathrm{Br}^{-}(\mathrm{aq}), 82.4 \mathrm{JK}^{-1} ; \mathrm{NO}_{2}(\mathrm{g}), 240.1 \mathrm{JK}^{-1} ; \mathrm{Br}_{2}(1), 152.2\) \(\mathrm{J} \mathrm{K}^{-1} ; \mathrm{HNO}_{2}(\mathrm{aq}), 135.6 \mathrm{JK}^{-1} .\) Determine (a) \(\Delta G^{\circ}\) at 298 K and (b) whether the reaction proceeds spontaneously in the forward or the reverse direction when reactants and products are in their standard states.

For the following equilibrium reactions, calculate \(\Delta G^{\circ}\) at the indicated temperature. [Hint: How is each equilibrium constant related to a thermodynamic equilibrium constant, \(K ?]\) (a) \(\mathrm{H}_{2}(\mathrm{g})+\mathrm{I}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g}) \quad K_{\mathrm{c}}=50.2\) at \(445^{\circ} \mathrm{C}\) (b) \(\mathrm{N}_{2} \mathrm{O}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})\) \(K_{c}=1.7 \times 10^{-13} \mathrm{at} 25^{\circ} \mathrm{C}\) (c) \(\mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NO}_{2}(\mathrm{g})\) \(K_{c}=4.61 \times 10^{-3}\) at \(25^{\circ} \mathrm{C}\) (d) \(2 \mathrm{Fe}^{3+}(\mathrm{aq})+\mathrm{Hg}_{2}^{2+}(\mathrm{aq}) \rightleftharpoons\) \(2 \mathrm{Fe}^{2+}(\mathrm{aq})+2 \mathrm{Hg}^{2+}(\mathrm{aq})\) \(K_{\mathrm{c}}=9.14 \times 10^{-6} \mathrm{at} 25^{\circ} \mathrm{C}\)

In your own words, define the following symbols: (a) \(\Delta S_{\text {univ }} ;\) (b) \(\Delta G_{f}^{0} ;\) (c) \(K\).

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