Use the following data to estimate the standard molar entropy of gaseous
benzene at \(298.15 \mathrm{K} ;\) that is, \(S^{\circ}\left[\mathrm{C}_{6}
\mathrm{H}_{6}(\mathrm{g}, 1 \mathrm{atm})\right] .\) For \(\mathrm{C}_{6}
\mathrm{H}_{6}(\mathrm{s}, 1 \mathrm{atm})\) at its melting
point of \(5.53^{\circ} \mathrm{C}, S^{\circ}\) is \(128.82 \mathrm{Jmol}^{-1}
\mathrm{K}^{-1}\). The enthalpy
of fusion is \(9.866 \mathrm{kJ} \mathrm{mol}^{-1} .\) From the melting point to
298.15 K, the average heat capacity of liquid benzene is \(134.0
\mathrm{JK}^{-1} \mathrm{mol}^{-1} .\) The enthalpy of vaporization of
\(\mathrm{C}_{6} \mathrm{H}_{6}(1)\) at \(298.15 \mathrm{K}\) is \(33.85
\mathrm{kJ} \mathrm{mol}^{-1},\) and in the vapor-
ization, \(\mathrm{C}_{6} \mathrm{H}_{6}(\mathrm{g})\) is produced at a pressure
of 95.13 Torr. Imagine that this vapor could be compressed to 1 atm pressure
without condensing and while behaving as an ideal gas. Calculate
\(S^{\circ}\left[\mathrm{C}_{6} \mathrm{H}_{6}(\mathrm{g}, 1 \text { atm) }] .[
\text { Hint: Refer to }\right.\) Exercise \(88,\) and note the following: For
infinitesimal quantities, \(d S=d q / d T ;\) for the compression of an ideal
gas, \(d q=-d w ;\) and for pressure-volume work, \(d w=-P d V\).