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Chapter 2: Problem 107

The mass of the isotope \(\frac{84}{36} \mathrm{Xe}\) is 83.9115 u. If the atomic mass scale were redefined so that \(\frac{84}{36} \mathrm{Xe}=84 \mathrm{u},\) exactly, the mass of the \(^{12} \mathrm{C}\) isotope would be (a) \(11.9115 \mathrm{u}\) (b) \(11.9874 \mathrm{u} ;\) (c) \(12 \mathrm{u}\) exactly; \((\mathrm{d}) 120127 \mathrm{u} ;(\mathrm{e}) 12.0885 \mathrm{u}\)

Short Answer

Expert verified
The mass of the carbon-12 isotope on the redefined atomic mass scale is 11.9874 u, so the correct answer is (b) 11.9874 u.

Step by step solution

01

Understanding Atomic Mass Scale

Atomic mass is usually measured in atomic mass units (amu) or in this case symbolized as 'u'. A mass scale is often defined with reference to a standard. By our current mass scale, an atom of \(^{12} \mathrm{C}\) mass is exactly 12 atomic mass units.
02

Redefine Atomic Mass Scale

In this problem, the atomic mass scale is redefined such that \(\frac{84}{36} \mathrm{Xe}\) is 84 u exactly. This means one atomic mass unit is now defined as \( \frac{83.9115 \ u}{84 \ u} \).
03

Calculate the New Mass of \(^{12} \mathrm{C}\)

Now, on this redefined scale, the mass of the carbon-12 isotope would be \(12 * \frac{83.9115 \ u}{84 \ u} = 11.9874 \ u\).

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Most popular questions from this chapter

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