There are three common iron-oxygen compounds. The one with the greatest proportion of iron has one Fe atom for every \(\mathrm{O}\) atom and the formula \(\mathrm{FeO}\). A second compound has 2.327 g Fe per \(1.000 \mathrm{g} \mathrm{O},\) and the third has \(2.618 \mathrm{g}\) Fe per \(1.000 \mathrm{g}\) O. What are the formulas of these other two iron-oxygen compounds?

Short Answer

Expert verified
The formula for the second compound is FeO and the formula for the third compound is Fe2O3.

Step by step solution

01

Find the Molar Masses of Fe and O

To start, we must find the molar masses of Iron (Fe) and Oxygen (O). Using a periodic table, we find that the molar mass of Fe is 55.845 g/mol and the molar mass of O is 16.00 g/mol.
02

Calculate Moles of Fe and O from Mass for the Second Compound

Given the mass of Fe and O in the second compound, we must calculate the amount in moles. We do this by dividing the given mass by the element's molar mass. So, moles of Fe = \(2.327g / 55.845g/mol = 0.0417mol\) and moles of O = \(1.000g / 16.00g/mol = 0.0625mol\)
03

Derive the Formula of the Second Compound

To derive the formula, we need to find the simplest whole number ratio of moles of Fe to O. Dividing each by the smallest number of moles we get a ratio of 1:1. Therefore the formula of the second compound is FeO.
04

Calculate Moles of Fe and O from Mass for the Third Compound

Similarly for the third compound we calculate the amount of Fe and O in moles: moles of Fe = \(2.618g / 55.845g/mol = 0.0469mol\), moles of O = \(1.000g / 16.00g/mol = 0.0625mol\)
05

Derive the Formula of the Third Compound

Again we find the simplest whole number ratio of moles of Fe to O by dividing each by the smallest number of moles. This gives a ratio of about 1:1. However, considering the experimental error, it's likely this ratio is 2:3. Therefore, the formula of the third compound is likely to be Fe2O3.

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