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Chapter 2: Problem 27

For the atom \(^{108}\) Pd with mass 107.90389 u, determine (a) the numbers of protons, neutrons, and electrons in the atom; (b) the ratio of the mass of this atom to that of an atom of \(^{12}_{6} \mathrm{H}\)

Short Answer

Expert verified
The atom \(^{108}\)Pd has 46 protons, 46 electrons and 62 neutrons. The ratio of its mass to that of \(^{12}_{6}\mathrm{H}\) is approximately \( \frac{107.90389}{12} = 8.99 \)

Step by step solution

01

Determine the Number of Protons and Electrons

The atomic number of Pd (Palladium) is 46 which is also the number of protons in the atom. Because the atom is neutral, the number of electrons is also 46.
02

Determine the Number of Neutrons

The atomic mass number is 108 (this is the superscripted number), which is the sum of protons and neutrons. Subtract the number of protons from the atomic mass number: \(108 - 46 = 62\) So, there are 62 neutrons in the atom.
03

Determine the Ratio of Atomic Masses

The atomic mass of \(^{108}\)Pd is given as 107.90389 u and the atomic mass of \(^{12}_{6}\mathrm{H}\) is exactly 12 u (by definition). So, the ratio of the atomic mass of \(^{108}\)Pd to \(^{12}_{6}\mathrm{H}\) is \( \frac{107.90389}{12} \)

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Most popular questions from this chapter

Monel metal is a corrosion-resistant copper-nickel alloy used in the electronics industry. A particular alloy with a density of \(8.80 \mathrm{g} / \mathrm{cm}^{3}\) and containing \(0.022 \%\) Si by mass is used to make a rectangular plate \(15.0 \mathrm{cm}\) long, \(12.5 \mathrm{cm}\) wide, \(3.00 \mathrm{mm}\) thick, and has a \(2.50 \mathrm{cm}\) diameter hole drilled through its center. How many silicon- 30 atoms are found in this plate? The mass of a silicon- 30 atom is \(29.97376 \mathrm{u}\) and the percent natural abundance of silicon- 30 is 3.10\%.

Determine the only possible isotope (E) for which the following conditions are met: \(\bullet\)The mass number of \(\mathrm{E}\) is 2.50 times its atomic number. \(\bullet\)The atomic number of \(\mathrm{E}\) is equal to the mass number of another isotope (Y). In turn, isotope Y has a neutron number that is 1.33 times the atomic number of \(Y\) and equal to the neutron number of selenium- 82 .

Identify the isotope \(X\) that has one more neutron than protons and a mass number equal to nine times the charge on the ion \(X^{3+}\)

A particular silver solder (used in the electronics industry to join electrical components) is to have the atom ratio of \(5.00 \mathrm{Ag} / 4.00 \mathrm{Cu} / 1.00 \mathrm{Zn}\). What masses of the three metals must be melted together to prepare \(1.00 \mathrm{kg}\) of the solder?

The German chemist Fritz Haber proposed paying off the reparations imposed against Germany after World War I by extracting gold from seawater. Given that (1) the amount of the reparations was \(\$ 28.8\) billion dollars, (2) the value of gold at the time was about \(\$ 21.25\) per troy ounce ( \(1 \text { troy ounce }=31.103 \mathrm{g}),\) and (3) gold occurs in seawater to the extent of \(4.67 \times 10^{17}\) atoms per ton of seawater \((1 \text { ton }=2000\) lb), how many cubic kilometers of seawater would have had to be processed to obtain the required amount of gold? Assume that the density of seawater is \(1.03 \mathrm{g} / \mathrm{cm}^{3}\) (Haber's scheme proved to be commercially infeasible, and the reparations were never fully paid.)
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