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Chapter 2: Problem 33

Which of the following species has (a) equal numbers of neutrons and electrons; (b) protons, neutrons, and electrons in the ratio 9: 11: 8 ; (c) a number of neutrons equal to the number of protons plus one-half the number of electrons? $^{24} \mathrm{Mg}^{2+},^{47} \mathrm{Cr},^{60} \mathrm{Co}^{3+},^{35} \mathrm{Cl}^{-},^{124} \mathrm{Sn}^{2+},^{226} \mathrm{Th},^{90} \mathrm{Sr}$

Short Answer

Expert verified
The atom with equal numbers of neutrons and electrons is \(^{24} \mathrm{Mg}^{2+}\). The atom that has protons, neutrons, and electrons in the ratio 9:11:8 is \(^{60} \mathrm{Co}^{3+}\). The atom that has a number of neutrons equal to the number of protons plus one-half the number of electrons is \(^{35} \mathrm{Cl}^{-}\).

Step by step solution

01

Identify numbers for each atom

Firstly, identify the number of protons, neutrons, and electrons for each of the given species. For instance, for \(^{24}Mg^{2+}\), the atomic number of Mg (Magnesium) is 12, so it has 12 protons. It has \(24 - 12 = 12\) neutrons, and since it is a cation with charge \(2+\), it has \(12 - 2 = 10\) electrons.
02

Solve part (a)

For part (a), you have to find an atomic species with equal numbers of neutrons and electrons. Check which among the identified species has got an equal number of neutrons and electrons.
03

Solve part (b)

For part (b), find an atomic species that has protons, neutrons, and electrons in the ratio 9:11:8. By comparing the numbers derived above, find out the species which has a 9:11:8 relation among protons, neutrons and electrons.
04

Solve part (c)

For part (c), find an atomic species in which the number of neutrons is equal to the number of protons plus half of the electrons. By using the results derived from step 1, find out the species that holds true for this condition.

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