Determine the only possible isotope (E) for which the following conditions are met: \(\bullet\)The mass number of \(\mathrm{E}\) is 2.50 times its atomic number. \(\bullet\)The atomic number of \(\mathrm{E}\) is equal to the mass number of another isotope (Y). In turn, isotope Y has a neutron number that is 1.33 times the atomic number of \(Y\) and equal to the neutron number of selenium- 82 .

Short Answer

Expert verified
The isotope E that fits the given conditions is silicon-36 (Si-36).

Step by step solution

01

Define the known and unknown variables

Let's denote the atomic number of isotope E as Z1 and its mass number as A1. The atomic number 'Z' and the mass number 'A' for Y are Z2 and A2 respectively. From the given conditions, the following relationships are obtained: A1 = 2.5 * Z1, Z2 = A1, and Number of neutrons in Y = 1.33 * Z2 = 48.
02

Solve the equations

By plugging Z2 = A1 into the third equation gives 1.33 * A1 = 48. Solving for A1 gives A1 = 48 / 1.33, which results in A1 = 36 (rounded to the nearest whole number).
03

Determine the atomic number of E

Knowing the value of A1, we can use the equation A1 = 2.5 * Z1 to calculate Z1. Substituting A1 = 36 into the equation gives Z1 = A1 / 2.5, which results in Z1 = 36 / 2.5 = 14.4, roughly rounded to the nearest whole number gives Z1 = 14.
04

Identify isotope E

From the periodic table, the element with the atomic number 14 is silicon (Si). So, the isotope E is silicon-36 (Si-36).

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