A particular silver solder (used in the electronics industry to join electrical components) is to have the atom ratio of \(5.00 \mathrm{Ag} / 4.00 \mathrm{Cu} / 1.00 \mathrm{Zn}\). What masses of the three metals must be melted together to prepare \(1.00 \mathrm{kg}\) of the solder?

Short Answer

Expert verified
Based on the given atom ratio, the approximate masses of Silver (Ag), Copper (Cu), and Zinc (Zn) in the solder are 704.6 g, 331.4 g, and 85.6 g respectively. The total mass is equal to 1.00 kg or 1000 g as requested in the question.

Step by step solution

01

Calculate the molar mass of each metal

The molar mass of Silver (Ag) is approximately \(107.87 \, g/mol\), Copper (Cu) is \(63.55 \, g/mol\), and Zinc (Zn) is \(65.38 \, g/mol\). These values are available in the periodic table.
02

Calculate the total molar mass of the solder

The total molar mass of the solder is the total molar mass based on the ratio of the atoms. In this case, the total molar mass \(= (5 × molar \, mass \, of \, Ag) + (4 × molar \, mass \, of \, Cu) + (1 × molar \, mass \, of \, Zn) = (5 × 107.87) + (4 × 63.55) + (1 × 65.38) = 766.6 \, g/mol\).
03

Calculate the mass of each metal in the solder

To find out the mass of each metal in the solder, we first calculate the proportion of each metal in the total molar mass. This can be done as follows: - For Silver (Ag): \((5 × molar \, mass \, of \, Ag) / total \, molar \, mass = (5 × 107.87) / 766.6\). - For Copper (Cu): \((4 × molar \, mass \, of \, Cu) / total \, molar \, mass = (4 × 63.55) / 766.6\).- For Zinc (Zn): \((1 × molar \, mass \, of \, Zn) / total \, molar \, mass = (1 × 65.38) / 766.6\).Next, we multiply each proportion by the total mass of the solder (1.00 kg or 1000 g) to find out the mass of each metal.

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